JPA - 查詢參數為null

Question

@Query("select users from User users  " +
        "where users.id like concat('%',?1,'%') and " +
        "users.name like concat('%',?2,'%') and " +
        "users.telNo like concat('%',?3,'%') ")
List<User> fuzzyQueryUser(Integer id, String name, String telNo);

當第一個參數id為null時，模糊查詢沒有結果。 如果參數為null，我希望在數據庫中有類似的條目時得到結果。 我該怎么辦？ 謝謝。

@Query("select users from User users  " +
    "where (users.id like concat('%',?1,'%') or ?1 is null or ?1 ='')and " +
    "(users.name like concat('%',?2,'%') or ?2 is null or ?2 ='') and " +
    "(users.telNo like concat('%',?3,'%') or ?3 is null or ?3 ='')")
List<User> fuzzyQueryUser(String id, String name, String telNo);

像這樣

@Query("select users from User users  " +
        "where (users.id like concat('%',?1,'%') or ?1 is null  )and " +
        "(users.name like concat('%',?2,'%') or ?2 is null or ?2 ='') and " +
        "(users.telNo like concat('%',?3,'%') or ?3 is null or ?3 ='')")
List<User> fuzzyQueryUser(Integer id, String name, String telNo);                        

Answer 1

只需添加另一個條件來忽略null和可選的空字符串：

@Query("select users from User users  " +
        "where (users.id like concat('%',?1,'%') or ?1 is null) and " 
       +"users.name like concat('%',?2,'%') and " +
        "users.telNo like concat('%',?3,'%') ")