繁体   English   中英

如何为此Django自定义标签编写测试用例

[英]How to write a test case for this Django custom tag

  • Django版本:v1.10
  • Python:3.5(这很重要,因为事实证明..查看答案)

我找到了这个答案,以便有一个if-else标签来比较Django模板中的request.path

https://stackoverflow.com/a/19895344/80353

from django import template
from django.template.base import Node, NodeList, TemplateSyntaxError

register = template.Library()

class IfCurrentViewNode(Node):
    child_nodelists = ('nodelist_true', 'nodelist_false')

    def __init__(self, view_name, nodelist_true, nodelist_false):
        self.view_name = view_name
        self.nodelist_true, self.nodelist_false = nodelist_true, nodelist_false

    def __repr__(self):
        return "<IfCurrentViewNode>"

    def render(self, context):
        view_name = self.view_name.resolve(context, True)
        request = context['request']
        if request.resolver_match.url_name == view_name:
            return self.nodelist_true.render(context)
        return self.nodelist_false.render(context)


def do_ifcurrentview(parser, token):
    bits = token.split_contents()
    if len(bits) < 2:
        raise TemplateSyntaxError("'%s' takes at least one argument"
                                  " (path to a view)" % bits[0])
    view_name = parser.compile_filter(bits[1])
    nodelist_true = parser.parse(('else', 'endifcurrentview'))
    token = parser.next_token()
    if token.contents == 'else':
        nodelist_false = parser.parse(('endifcurrentview',))
        parser.delete_first_token()
    else:
        nodelist_false = NodeList()
    return IfCurrentViewNode(view_name, nodelist_true, nodelist_false)

@register.tag
def ifcurrentview(parser, token):
    """
    Outputs the contents of the block if the current view match the argument.

    Examples::

        {% ifcurrentview 'path.to.some_view' %}
            ...
        {% endifcurrentview %}

        {% ifcurrentview 'path.to.some_view' %}
            ...
        {% else %}
            ...
        {% endifcurrentview %}
    """
    return do_ifcurrentview(parser, token)

想知道是否存在编写测试用例以覆盖此自定义代码的方法吗?

我想维持我们的考试覆盖率

您应该能够使用模拟功能涵盖大部分(如果不是全部)内容。 例如,假设您要测试render函数:

from unittest.mock import Mock

def test_render_url_match(self):
    mock_request = Mock()
    matching_url_name = 'url_name'
    mock_nodelist_true, mock_nodelist_false = Mock(), Mock()
    mock_view_name = Mock()
    mock_view_name.resolve.return_value = matching_url_name
    mock_request.resolver_match.url_name = matching_url_name
    mock_context = {'request': mock_request}

    custom_node = IfCurrentViewNode(mock_view_name, mock_nodelist_true, mock_nodelist_false)
    custom_node.render(mock_context)

    # You can then test that the correct function was called:
    # you can change to `assert_called_once` if using Python 3.6
    mock_nodelist_true.render.assert_called_once_with(mock_context)

通过以这种方式设置return self.nodelist_true.render(context) ,我确保此request.resolver_match.url_name == view_name将为true,并单击以下行: return self.nodelist_true.render(context) 然后,您可以设置网址名称,以使它们不匹配并覆盖错误的情况。

然后,对于do_ifcurrentview函数,您还可以模拟出所需的任何部分。 也许您不想让parser.compile_filter返回您需要的东西。 只是模拟它并更改返回值:

with mock.patch('parser.compile_filter') as mock_compile_filter:
    mock_compile_filter.return_value = 'my_expected_view_name'

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM