[英]Python: List of dictionaries: How to - nice printout using sys.stdout
我有以下词典列表 :
[{'Sequence': 'TGACCCTGCTTGGCGATCCCGGCGTTTC', 'Start': '52037', 'Strand': '+', 'End': '52064'}, {'Sequence': 'TGATCGCGCAACTGCAGCGGGAGTTAC', 'Start': '188334', 'Strand': '+', 'End': '188360'}, {'Sequence': 'TGATCCGGCACTCGTTGGAGTTCGTATC', 'Start': '245882', 'Strand': '+', 'End': '245909'}, {'Sequence': 'TGACCTTGGTCAGATCGATGACCGTAAT', 'Start': '318422', 'Strand': '+', 'End': '318449'}, {'Sequence': 'TGACCCGCGTATTTTGGAGCAGAAGTATC', 'Start': '343421', 'Strand': '+', 'End': '343449'}, {'Sequence': 'TGATCCGGCACTCGTTGGAGTTCGTATC', 'Start': '359576', 'Strand': '+', 'End': '359603'}, {'Sequence': 'TGATCGGCAATTCCTATGGCAAGTATC', 'Start': '457457', 'Strand': '+', 'End': '457483'}, {'Sequence': 'TGATCGAGGCGCCAGTTGTGCCCGTATT', 'Start': '627296', 'Strand': '+', 'End': '627323'}, {'Sequence': 'TGATCCAAGTGAACCCCCGCCCAGTAAA', 'Start': '637265', 'Strand': '+', 'End': '637292'}, {'Sequence': 'TGACCGGAAGACCGCCGTCGAGCGTATC', 'Start': '829035', 'Strand': '+', 'End': '829062'}, {'Sequence': 'TGATCGCGGCACCGACACCGGTCGTAAT', 'Start': '864440', 'Strand': '+', 'End': '864467'}, {'Sequence': 'TGATCGTTTCCGTGCTCGGAGCGTATC', 'Start': '934160', 'Strand': '+', 'End': '934186'}, {'Sequence': 'TGACCTGGCTCGAGGCCTGAGGAGTAAA', 'Start': '1162006', 'Strand': '+', 'End': '1162033'}, {'Sequence': 'TGACCCGCCGCAACATCCCCTTCGTAAA', 'Start': '1294515', 'Strand': '+', 'End': '1294542'}]
我想获取以下输出( 通过sys.stdout重定向打印 ):
Start:1234 End:5678 Strand:+ Sequence:ABCDEFG
...
到目前为止,我的想法涉及遍历列表并使用get方法获取键的值,然后进行手动打印 ,基本上是这样的:
for item in dictList:
print("Start"+item.get('Start'))
print("End"+item.get('End'))
...
我不确定如何处理换行符 。 我读过有关sys.stdout flush以避免换行的信息,但是由于我不想避免所有换行,所以我不确定这是否适合我的目标。
有更聪明/更短的方法来做到这一点吗?
感谢Aleksey,我想将我的印刷声明更改为:
for item in dictList:
print("Start"+str(item.get('Start'))+" "+"End"+str(item.get('End'))+" "+"Strand"+str(item.get('Strand'))+" "+"Sequence: "+str(item.get('Sequence')))
到目前为止,我坚持这一点:
print(ecf+" "+replicon+" - "+"Validated results: Total number of hits: "+str(len(finalList)))
print("")
for item in finalList:
print("Start: "+str(item.get('Start'))+" "+"End: "+str(item.get('End'))+" "+"Strand: "+str(item.get('Strand'))+" "+"Sequence: "+str(item.get('Sequence')))
打印:
ECF02 pSymA - Validated results: Total number of hits: 284
Start: 2876 End: 2903 Strand: + Sequence: GAACTACAGGAAGTTCATGGTCTCCTTC
Start: 2876 End: 2900 Strand: + Sequence: GAACTACAGGAAGTTCATGGTCTCC
Start: 9214 End: 9238 Strand: + Sequence: GAACGTCGGGCGCAAGAGCCGCTTT
...
请注意:dictList被finalList取代。 由于我的脚本的某些部分在这些打印之前运行
只需用以下结尾来避免换行:
print("Start"+item.get('Start'), end=" ")
end=" "
将继续您的字符串而无需换行
您可以使用.format_map(each_dic)
或更高版本的Python 3.5+添加的替代.format(**each_dic)
。 使用格式设置的每个打印中列表中的每个字典。
for each_dic in dictList:
print('Sequence: {Sequence:<29} '
'Start: {Start:>7} '
'Strand: {Strand} '
'End: {End:>7}'.format_map(each_dic))
查看Python帮助页面: string-常见的字符串操作,以获取更多参考和示例。
摘自我的更新,灵感来自Aleksey Solovey
print(ecf+" "+replicon+" - "+"Validated results: Total number of hits: "+str(len(finalList)))
print("")
for item in finalList:
print("Start: "+str(item.get('Start'))+" "+"End: "+str(item.get('End'))+" "+"Strand: "+str(item.get('Strand'))+" "+"Sequence: "+str(item.get('Sequence')))
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