[英]SQL query ORDER BY with WHERE clause
我有2张桌子。 第一个具有订户信息:
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| id | first_name | last_name | mail |
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| 1 | Jean | Bono | jean@bono.com |
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| 2 | Paul | Dodu | paule@dodu.com|
--------------------------------------------------------
第二个带有自定义字段:
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| id | subscriber_id | custom_field_id | value |
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| 1 | 1 | 1 | Photographer |
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| 2 | 1 | 2 | 00000000 |
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| 3 | 2 | 1 | Journalism|
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| 4 | 2 | 2 | 00000000 |
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我想按ID = 1的值或按字符串值(不是int)对订户进行排序。
例如,首先是所有“新闻业”,其次是所有“摄影师”
这是我的SQL查询(测试):
SELECT sub.*, cf.*
FROM subscribers AS sub
JOIN subscriber_custom_field AS cf
ON cf.subscriber_id = sub.id
WHERE sub.status = 'subscribed'
ORDER BY cf.value
但是此SQL查询错误会导致混合电话号码和字符串...
任何想法 ?
谢谢 !
如果要按custom_field_id = 1值进行排序,则必须在该字段上添加WHERE条件,但是您将只链接具有custom field = 1的行:
SELECT sub.*, cf.value as type
FROM subscribers AS sub
JOIN subscriber_custom_field AS cf
ON cf.subscriber_id = sub.id
WHERE sub.status = 'subscribed'
AND cf.custom_field_id = 1
ORDER BY cf.value
如果您还需要选择其他自定义字段,则我认为您必须完全更改SQL,使用子查询转换列中的行,否则将为每个自定义字段获得一行:
SELECT sub.*,
(SELECT cf.value FROM subscriber_custom_field WHERE cf.subscriber_id = subscriber_id AND custom_field_id = 1) AS type,
(SELECT cf.value FROM subscriber_custom_field WHERE cf.subscriber_id = subscriber_id AND custom_field_id = 2 LIMIT 1) AS phone
FROM subscribers AS sub
JOIN subscriber_custom_field AS cf
ON cf.subscriber_id = sub.id
WHERE sub.status = 'subscribed'
ORDER BY (SELECT cf.value FROM subscriber_custom_field WHERE cf.subscriber_id = subscriber_id AND custom_field_id = 1)
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