[英]sql query group by day of month
我有一个记录表,其中包含创建的行的日期。 (Oracle数据库)
ID City CreateDate
1 city-1 12.12.2017
1 city-2 13.12.2017
1 city-1 13.12.2017
1 city-3 12.12.2017
....
....
我想在一个月内创建一份每日报告。 例如12月天数的City-1报告
Day Count
1 10
2 80
3 60
4 10
...
30 11
我认为您可以将提取与计数功能一起使用:
SELECT EXTRACT(day FROM CreateDate) "Day",
COUNT(CreateDate) "Number of Reports"
FROM yourTableName
GROUP BY EXTRACT(day FROM CreateDate)
ORDER BY "Number of Reports" ASC;
如果我正确理解,以下查询将生成您想要的12月份的报告。
SELECT EXTRACT(day FROM CreateDate) "Day", COUNT(*) "Count" FROM your_record_table WHERE EXTRACT(month FROM CreateDate) = 12 GROUP BY EXTRACT(day FROM CreateDate) ORDER BY EXTRACT(day FROM CreateDate);
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