[英]Adding Unique Slug in Django
我正在尝试在学校项目中添加一个子弹字段,这是我在模型中尝试的内容,
def pre_save_receiver(sender, instance, *args, **kwargs):
slug = slugify(instance.title)
exists = Data.objects.filter(slug=slug).exists()
if exists:
instance.slug = "%s-%s" % (slug, instance.id)
else:
instance.slug = slug
pre_save.connect(pre_save_receiver, sender=Data)
一切工作正常,但问题是,即使它是唯一的,它也会在子域中添加ID。 我该如何解决?
模型至少具有以下内容:
class YourModel(models.Model):
title = models.CharField(max_length=120)
slug = models.SlugField(blank=True, null=True)
您需要在应用程序文件夹中创建一个名为utils的文件,其中包含以下代码:
utils.py
from django.utils.text import slugify
def random_string_generator(size=10, chars=string.ascii_lowercase + string.digits):
return ''.join(random.choice(chars) for _ in range(size))
def unique_slug_generator(instance, new_slug=None):
if new_slug is not None:
slug = new_slug
else:
slug = slugify(instance.title)
Klass = instance.__class__
qs_exists = Klass.objects.filter(slug=slug).exists()
if qs_exists:
new_slug = "{slug}-{randstr}".format(
slug=slug,
randstr=random_string_generator(size=4)
)
return unique_slug_generator(instance, new_slug=new_slug)
return slug
型号
from django.db.models.signals import pre_save, post_save
from .utils import unique_slug_generator
def pre_save_receiver(sender, instance, *args, **kwargs):
if not instance.slug:
instance.slug = unique_slug_generator(instance)
pre_save.connect(pre_save_receiver, sender=YourModel)
您正在尝试获取不存在的模型的ID。 在保存模型之前进行pre_save信号调用。 代替pre_save使用post_save信号
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