[英]How to send data from controller to model with CodeIgniter through functions
我想将数据从Controller传递到模型,但是我无法在CI的模型端获取它。请帮我。
这是我的控制器功能:
function show_chronicles($chronicle_num) {
$this->load->database();
//load the model
$this->load->model('Chronicles_model');
//load the method of model
$data['h'] = $this->Chronicles_model->show_seminar();
//return the data in view
$this->load->view('chronicles', $chronicle_num);
}
这是我的模型 :
public function show_seminar($chronicle_num) {
echo $chronicle_num;
//$this->db->select('*');
//$this->db->where('chronicles_no',$chronicle_num);
//$query1 = $this->db->get('chronicles');
//return $query1;
}
这是因为您没有将任何值传递给模型。
CONTROLLER
function show_chronicles($chronicle_num)
{
$this->load->database();
$this->load->model('Chronicles_model');
$data['h']=$this->Chronicles_model->show_seminar($chronicle_num);
$this->load->view('chronicles', $chronicle_num);
}
并且您需要返回查询的result()
模型
public function show_seminar($chronicle_num = NULL)
{
return $this->db
->get_where('chronicles', array('chronicles_no' => $chronicle_num))
->result();
}
控制器 :
function show_chronicles($chronicle_num) {
$this->load->database();
//load the model
$this->load->model('Chronicles_model');
//load the method of model
// pass it to model
$data['chronicle_num'] = $this->Chronicles_model->show_seminar($chronicle_num);
//return the data in view
$this->load->view('chronicles', $data);
}
这是我的模型 :
public function show_seminar($chronicle_num) {
return $chronicle_num;
//$this->db->select('*');
//$this->db->where('chronicles_no',$chronicle_num);
//$query1 = $this->db->get('chronicles');
//return $query1;
}
您只是在调用$this->Chronicles_model->show_seminar();
时忘了传递$chronicle_num
作为参数$this->Chronicles_model->show_seminar();
。
所以正确的方法是$this->Chronicles_model->show_seminar($chronicle_num);
您可以向功能添加任意数量的参数。 例:
public function show_seminar($chronicle_num, $param2, $param3) {
//Login here
}
只要记住每次调用该函数时都要传递参数即可。
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