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[英]How to get aggregation class properties of a Elasticsearch NEST response?
[英]ElasticSearch NEST GET response not deserialized
我们从第三方连接到ElasticSearch,以使用NEST nuget包获取一些数据。 但是,如果使用GET <>调用,则在强类型POCO中不会反序列化响应。 HTTP调用成功,并且体内有一个带有数据的json对象。
var result = _elasticSearchClient.Get<Contractor>(188153, request => request
.Index("{index_name}")
.Type("{type_name}"));
--POCO. Naming of the property as in the json message
public class Contractor
{
public int contractor_id { get; set; }
public string type { get; set; }
public string type_description { get; set; }
public string contractor_code { get; set; }
public string name { get; set; }
...
}
使用HttpClient和JsonCovert进行反序列化的调用
var response = Task.Run(() => _httpClient.GetAsync(url)).Result;
var responseMessage = Task.Run(() => response.Content.ReadAsStringAsync()).Result;
var contractor = JsonConvert.DeserializeObject<Contractor>(responseMessage);
ElasticSearchClient的配置
var url = new Uri($"{BaseUrl}");
var connectionSettings = new ConnectionSettings(url);
connectionSettings.ClientCertificate(GetCertificateFromStore());
connectionSettings.BasicAuthentication(Username, Password);
connectionSettings.ThrowExceptions();
connectionSettings.PrettyJson();
connectionSettings.DisableDirectStreaming();
connectionSettings.DefaultFieldNameInferrer(p => p);
var elasticSearchClient = new ElasticClient(connectionSettings);
DebugInformation:有效的NEST响应是由对GET的成功低级调用生成的:/ {index_name} / {type_name} / 188153?pretty = true
此API调用的审核跟踪:-[1] HealthyResponse:节点:https:// {baseUrl} /接收:00:00:01.0835021请求:请求流未捕获或已被序列化程序读取完成。 在ConnectionSettings上设置DisableDirectStreaming()以强制在响应上进行设置。
响应:
{
"_index" : "{index_name}",
"_type" : "{type_name}",
"_id" : "188153",
"_version" : 1,
"found" : true,
"_source" : {
"contractor" : {
"contractor_id" : 188153,
"type" : "OVE",
"type_description" : "Overig",
"contractor_code" : "RES0000826",
"name" : "OrganizationName",
}
}
NEST NuGet软件包5.6.0
Elasticsearch 6.0.0版
我想念什么?
NEST不会反序列化它,因为Elasticsearch中的_source
文档是一个具有一个属性"contractor"
的对象,其值是一个包含属性的对象。
为了正确反序列化,Elasticsearch中的_source
文档需要
"_source" : {
"contractor_id" : 188153,
"type" : "OVE",
"type_description" : "Overig",
"contractor_code" : "RES0000826",
"name" : "OrganizationName"
}
或者 ,POCO应该类似于
public class ContractorWrapper //choose any type name you like :)
{
public Contractor contractor { get;set; }
}
匹配JSON结构。
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