[英]Replacing words with spaces within a tibble in R without anti-join
我有类似这样的句子:
小标题:1,782 x 1
Chat
<chr>
1 Hi i would like to find out more about the trials
2 Hello I had a guest
3 Hello my friend overseas right now
...
我想做的是删除停用词,例如“ I”,“ hello”。 我已经有了它们的列表,并且想用空格替换这些停用词。 我尝试使用mutate和gsub,但它只接受一个正则表达式。 反连接在这里不起作用,因为我正在尝试使用双字组/三字组。我没有一个单词列来反连接停用词。
有没有办法替换R中每个句子中的所有这些单词?
我们可以replace
标记的嵌套,用空格( " "
) replace
'stop_words''word'列中找到的'word',并在按'lines'分组后paste
'word'
library(tidytext)
library(tidyverse)
rowid_to_column(df1, 'lines') %>%
unnest_tokens(word, Chat) %>%
mutate(word = replace(word, word %in% stop_words$word, " ")) %>%
group_by(lines) %>%
summarise(Chat = paste(word, collapse=' ')) %>%
ungroup %>%
select(-lines)
注意:这会将“ stop_words”数据集中找到的停用词替换为" "
如果我们只需要替换停用词的自定义子集,则创建这些元素的vector
并在mutate
步骤中进行更改
v1 <- c("I", "hello", "Hi")
rowid_to_column(df1, 'lines') %>%
...
...
mutate(word = replace(word %in% v1, " ")) %>%
...
...
我们可以使用“ \\\\b
停用词\\\\b
”构造一个模式,然后使用gsub
将其替换为“”。 这是一个例子。 请注意,我将ignore.case = TRUE
设置为同时包含小写和大写字母,但是您可能需要根据需要进行调整。
dat <- read.table(text = "Chat
1 'Hi i would like to find out more about the trials'
2 'Hello I had a guest'
3 'Hello my friend overseas right now'",
header = TRUE, stringsAsFactors = FALSE)
dat
# Chat
# 1 Hi i would like to find out more about the trials
# 2 Hello I had a guest
# 3 Hello my friend overseas right now
# A list of stop word
stopword <- c("I", "Hello", "Hi")
# Create the pattern
stopword2 <- paste0("\\b", stopword, "\\b")
stopword3 <- paste(stopword2, collapse = "|")
# View the pattern
stopword3
# [1] "\\bI\\b|\\bHello\\b|\\bHi\\b"
dat$Chat <- gsub(pattern = stopword3, replacement = " ", x = dat$Chat, ignore.case = TRUE)
dat
# Chat
# 1 would like to find out more about the trials
# 2 had a guest
# 3 my friend overseas right now
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