使用 python -selenium 进行网页抓取

Question

我想从“新闻”类中抓取所有 href 内容（代码中提到了网址），我尝试了这段代码，但它不起作用......

代码：

from bs4 import BeautifulSoup
from selenium import webdriver

Base_url = "http://www.thehindubusinessline.com/stocks/abb-india-ltd/overview/"

driver = webdriver.Chrome()
driver.set_window_position(-10000,-10000)
driver.get(Base_url)

html = driver.page_source
soup = BeautifulSoup(html, 'html.parser')

for div in soup.find_all('div', class_='news'):  
    a = div.findAll('a')   
    print(a['href'])

谢谢

Answer 1

您想要的内容位于框架内：

<iframe width="100%" frameborder="0" src="http://hindubusiness.cmlinks.com/Companydetails.aspx?&cocode=INE117A01022" id="compInfo" height="600px">...</iframe>

所以，首先你必须切换到那个框架。 您可以通过添加这些行来做到这一点：

driver.switch_to.default_content()
driver.switch_to.frame('compInfo')

完整代码（使其无头）：

from bs4 import BeautifulSoup
from selenium import webdriver
from selenium.webdriver.chrome.options import Options

Base_url = "http://www.thehindubusinessline.com/stocks/abb-india-ltd/overview/"

chrome_options = Options()
chrome_options.add_argument("--headless")
driver = webdriver.Chrome(chrome_options=chrome_options)
driver.get(Base_url)
driver.switch_to.frame('compInfo')
soup = BeautifulSoup(driver.page_source, 'lxml')
for link in soup.select('.news a'):  
    print(link['href'])

输出：

/HomeFinancial.aspx?&cocode=INE117A01022&Cname=ABB-India-Ltd&srno=17040010444&opt=9
/HomeFinancial.aspx?&cocode=INE117A01022&Cname=ABB-India-Ltd&srno=17038039002&opt=9
/HomeFinancial.aspx?&cocode=INE117A01022&Cname=ABB-India-Ltd&srno=17019039003&opt=9
/HomeFinancial.aspx?&cocode=INE117A01022&Cname=ABB-India-Ltd&srno=17019038003&opt=9
/HomeFinancial.aspx?&cocode=INE117A01022&Cname=ABB-India-Ltd&srno=17019010085&opt=9

Answer 2

像这样的事情会起作用：

for div in soup.find_all('article', 'news'):
    a = div.findAll('a')
    links = [article['href'] for article in a ]
    print(links)