如何比较两个数组对象并从一个数组对象中删除匹配的对象

Question

我的代码方案是：

var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
{name:"madhu",htno:1247},{name:"ranga",htno:1248}]

var seletedEmployees= [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = [?];

Answer 1

您可以将选定的雇员姓名存储在一个数组中，然后过滤“雇员”数组并检查该雇员的姓名是否在此数组中：

 var employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},{name:"madhu",htno:1247},{name:"ranga",htno:1248}] var selectedEmployees= ["mohan","ranga"]; var result = employees.filter(emp => selectedEmployees.includes(emp.name)); console.log(result); 

要以编程方式获取字符串数组而不是对象数组，可以使用map ：

var seletedEmployees= [{name:"mohan"},{name:"ranga"}].map(emp => emp.name);

Answer 2

您可以尝试以下方法：

var Employees = [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
    {name:"madhu",htno:1247},{name:"ranga",htno:1248}] 

var seletedEmployees = [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = Employees.filter(name => {
  return (name.name !== seletedEmployees[0].name && name.name !== seletedEmployees[1].name)
}) 

console.log(employeesdataAfterremoveSelected)

Answer 3

从上面给出的代码中，我认为这可能有效

$.each(student, function(key, value){
   if(matchedvalues.indexOf(value.name) < 0)
     {
       employeesdataAfterremoveSelected.push(value.name);
     }
})

Answer 4

这是一个班轮，分解来解释：

// Start by filtering the first array on a condition.
employeesdataAfterremoveSelected = Employees.filter(
  // Map the array of selected employees to only return the name
  e => seletedEmployees.map(_e => _e.name)
    // use the includes function to check if the name is in the array
    .includes(e.name)
);

一行：

employeesdataAfterremoveSelected = Employees.filter(e => seletedEmployees.map(_e => _e.name).includes(e.name));

Answer 5

您可以使用过滤器方法，如下所示（未经测试）

var Employees = [{name:"Ram",htno:1245}, {name:"mohan",htno:1246}]

var SelectedEmployess = [{name:"Ram",htno:1245}]

// filter the items from the invalid list, out of the complete list
    var employeesdataAfterremoveSelected = Employees.filter((item.name) => {
    return !SelectedEmployess.has(item.name);
})

// get a Set of the distinct, valid items
var validItems = new Set(employeesdataAfterremoveSelected);

Answer 6

var Employees = [{{name：“ Ram”，htno：1245}，{name：“ mohan”，htno：1246}，{name：“ madhu”，htno：1247}，{name：“ ranga”，htno：1248 }]

var seletedEmployees = [{{name：“ mohan”}，{name：“ ranga”}]];

var EmployeesdataAfterremoveSelected = Employees.filter（function（val，index）{console.log（val.name）return！（seletedEmployees.map（function（e）{return e.name;}）。indexOf（val.name））;; }）;