如何比較兩個數組對象並從一個數組對象中刪除匹配的對象

Question

我的代碼方案是：

var Employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
{name:"madhu",htno:1247},{name:"ranga",htno:1248}]

var seletedEmployees= [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = [?];

Answer 1

您可以將選定的雇員姓名存儲在一個數組中，然后過濾“雇員”數組並檢查該雇員的姓名是否在此數組中：

 var employees= [{name:"Ram",htno:1245},{name:"mohan",htno:1246},{name:"madhu",htno:1247},{name:"ranga",htno:1248}] var selectedEmployees= ["mohan","ranga"]; var result = employees.filter(emp => selectedEmployees.includes(emp.name)); console.log(result); 

要以編程方式獲取字符串數組而不是對象數組，可以使用map ：

var seletedEmployees= [{name:"mohan"},{name:"ranga"}].map(emp => emp.name);

Answer 2

您可以嘗試以下方法：

var Employees = [{name:"Ram",htno:1245},{name:"mohan",htno:1246},
    {name:"madhu",htno:1247},{name:"ranga",htno:1248}] 

var seletedEmployees = [{name:"mohan"},{name:"ranga"}];

var employeesdataAfterremoveSelected = Employees.filter(name => {
  return (name.name !== seletedEmployees[0].name && name.name !== seletedEmployees[1].name)
}) 

console.log(employeesdataAfterremoveSelected)

Answer 3

從上面給出的代碼中，我認為這可能有效

$.each(student, function(key, value){
   if(matchedvalues.indexOf(value.name) < 0)
     {
       employeesdataAfterremoveSelected.push(value.name);
     }
})

Answer 4

這是一個班輪，分解來解釋：

// Start by filtering the first array on a condition.
employeesdataAfterremoveSelected = Employees.filter(
  // Map the array of selected employees to only return the name
  e => seletedEmployees.map(_e => _e.name)
    // use the includes function to check if the name is in the array
    .includes(e.name)
);

一行：

employeesdataAfterremoveSelected = Employees.filter(e => seletedEmployees.map(_e => _e.name).includes(e.name));

Answer 5

您可以使用過濾器方法，如下所示（未經測試）

var Employees = [{name:"Ram",htno:1245}, {name:"mohan",htno:1246}]

var SelectedEmployess = [{name:"Ram",htno:1245}]

// filter the items from the invalid list, out of the complete list
    var employeesdataAfterremoveSelected = Employees.filter((item.name) => {
    return !SelectedEmployess.has(item.name);
})

// get a Set of the distinct, valid items
var validItems = new Set(employeesdataAfterremoveSelected);

Answer 6

var Employees = [{{name：“ Ram”，htno：1245}，{name：“ mohan”，htno：1246}，{name：“ madhu”，htno：1247}，{name：“ ranga”，htno：1248 }]

var seletedEmployees = [{{name：“ mohan”}，{name：“ ranga”}]];

var EmployeesdataAfterremoveSelected = Employees.filter（function（val，index）{console.log（val.name）return！（seletedEmployees.map（function（e）{return e.name;}）。indexOf（val.name））;; }）;