将字典转换为字典python列表

Question

我想转换以下字典：

{'Stockholm': ['235', '35'], 'Helsinki': ['285', '15'], 
'Copenhagen': ['180', '60'], 'Berlin': ['185', '85'], 
'Prague': ['190', '115'], 'Warsaw': ['260', '105'], 
'Moscow': ['370', '80'], 'Sofia': ['275', '170'], 
'Ankara': ['340', '190'], 'Athens': ['285', '205']}

变成：

[{'Stockholm':['235', '35']},{'Helsinki': ['285', '15']},
{'Copenhagen':   ['180', '60']},...,{'Athens': ['285', '205']}] 

我不知道如何转换它。

Answer 1

您可以对dict.items()对使用列表理解：

[{k: v} for k, v in d.items()]  # where d is your dictionary

这将为每个键值对创建一个单独的字典。

您不能依赖输入字典中的任何顺序，因此输出顺序将取决于字典的插入和删除历史记录（除非您使用的是Python 3.6或更高版本）。

演示：

>>> d = {'Stockholm': ['235', '35'], 'Helsinki': ['285', '15'],
... 'Copenhagen': ['180', '60'], 'Berlin': ['185', '85'],
... 'Prague': ['190', '115'], 'Warsaw': ['260', '105'],
... 'Moscow': ['370', '80'], 'Sofia': ['275', '170'],
... 'Ankara': ['340', '190'], 'Athens': ['285', '205']}
>>> [{k: v} for k, v in d.items()]
[{'Stockholm': ['235', '35']}, {'Helsinki': ['285', '15']}, {'Copenhagen': ['180', '60']}, {'Berlin': ['185', '85']}, {'Prague': ['190', '115']}, {'Warsaw': ['260', '105']}, {'Moscow': ['370', '80']}, {'Sofia': ['275', '170']}, {'Ankara': ['340', '190']}, {'Athens': ['285', '205']}]

Answer 2

简单的方法：

d = {'Stockholm': ['235', '35'], 'Helsinki': ['285', '15'], 
'Copenhagen': ['180', '60'], 'Berlin': ['185', '85'], 
'Prague': ['190', '115'], 'Warsaw': ['260', '105'], 
'Moscow': ['370', '80'], 'Sofia': ['275', '170'], 
'Ankara': ['340', '190'], 'Athens': ['285', '205']}
d = [d]