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如何使Angular组件UI等待异步功能

[英]How to make Angular component UI wait for Asynchronous function

我正在做的是,我正在预订一个http get函数,该函数可以在singup组件中验证我的用户。 现在,我想要的是等待直到获取数据并导航到内部页面。 验证成功后,我试图导航到内部页面。 但它仅在UI准备好后才起作用。 我的意思是刷新1秒钟后仍然看到注册页面。 代码如下

  this._restapiService.validate()
          .subscribe(data=>{
              if(data.success){
                this._router.navigate(['contacts']);
              }
          });

我试图将这段代码放在Constructor()和ngInit()中,但是正在发生同样的事情。

如@yurzui在评论部分中所述,如果防护验证失败(如果防护失败,则组件生命周期将不会触发),角度防护会阻止呈现视图。

检出此示例代码片段,可用于在应用程序中为经过验证的视图添加保护措施-

守卫定义

import { Injectable } from "@angular/core";
import { CanActivate, ActivatedRouteSnapshot, RouterStateSnapshot } from "@angular/router";

@Injectable()
export class LoggedInGuard implements CanActivate {

    constructor() { }

    public canActivate(route: ActivatedRouteSnapshot, state: RouterStateSnapshot): Promise<any> {
        return new Promise<any>((resolve: Function, reject: Function) => {
            //this is where you need to validate the user
            //it can be an AJAX call
            let response: any;
            //assuming the AJAX call is made here
            //response = HttpService.getData();

            //resolve indicates user is validated by the service and guard allows user to land on the reuqested view.
            //reject on the other hand, will stop user from landing on requested view
            //this logic can be customised.
            response.success ? resolve() : reject();
        });
    }
}

路线定义

import { Route } from "@angular/router";
import { HomeComponent } from "./components/home.component";
import { LoginComponent } from "./components/login.component";

export const routes: Route[] = [{
        path: "route",
        canActivate: [LoggedInGuard],
        component: HomeComponent,
    },{
        path: "*",
        component: LoginComponent,
    }];

请检查这个SO答案,以了解如何串联触发多个警卫,因为在大多数情况下,角度触发不会串联触发多个警卫。

我希望这可以帮助你。

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