[英]Neo4j cypher query: AllShortestPaths with specified nodes and relationship properties
我是Neo4j的新手。
我创建了以下示例:
// (Node2)
// / \
// Rel2 / \ Rel3
// / \
// (Node1) ------> (Node3)
// Rel1
//
// create nodes
CREATE
(n1:Node1{id:1,rights:["admin","user"]}),
(n2:Node2{id:2,rights:["admin","user"]}),
(n3:Node3{id:3,rights:["admin","user"]})
// create relationships
CREATE (n1)-[r1:Rel1{id:11,rights:["admin"]}]->(n3)
CREATE (n1)-[r2:Rel2{id:12,rights:["admin","user"]}]->(n2)
CREATE (n2)-[r3:Rel3{id:13,rights:["admin","user"]}]->(n3)
RETURN n1,n2,n3,r1,r2,r3
每个节点和关系都有一个带有一些权限值的属性数组。 我想创建一个查询,该查询为我提供具有指定属性的两个节点之间的(最短)路径。 例:
用户具有“管理员”权限,路径应为:
(节点1)-[角色1]->(节点3)
(每个节点和关系在'rights'属性中都有'admin'字符串。)
如果用户具有正确的“用户”,则路径应为:
(节点1)-[角色2]-(节点2)-[角色3]-(节点3)
(因为Rel1关系在'rights'属性中没有'user'字符串。)
最初,我尝试了这个有效的查询:
WITH ["admin","otherRight"] AS usersRights
MATCH path=allShortestPaths((n1:Node1{id:1})-[*..4]-(n2:Node3{id:3}))
WITH *, relationships(path) AS rels, nodes(path) as nodes
WHERE ANY (rel IN rels WHERE ANY(r IN rel.rights WHERE r IN usersRights))
AND ANY (node IN nodes WHERE ANY(r IN node.rights WHERE r IN usersRights))
RETURN path
然后,我用“用户”替换了“管理员”,但是此查询不起作用(没有鲁):
WITH ["user","otherRight"] AS usersRights
MATCH ... // same as above
...
RETURN path
以下查询与我所需的结果匹配,但是在这种情况下,我将不得不进行几次查询才能获得深度n的所需结果(最短路径)。
WITH ["user","otherRight"] AS usersRights
MATCH path=(n1:Node1{id:1})-[r1]-(n2)-[r2]-(n3:Node3{id:3})
WHERE ANY(r IN n1.rights WHERE r IN usersRights)
AND ANY(r IN r1.rights WHERE r IN usersRights)
AND ANY(r IN n2.rights WHERE r IN usersRights)
AND ANY(r IN r2.rights WHERE r IN usersRights)
AND ANY(r IN n3.rights WHERE r IN usersRights)
RETURN path
是否可以创建一个密码查询,使我得到不良结果?
谢谢。
您的第一个查询具有一个WITH
子句,该子句将MATCH
和WHERE
子句分隔开,从而防止WHERE
子句影响allshortestpath()
函数的行为。 因此,该函数仅返回最短路径,而不测试节点和关系。
试试这个,代替:
WITH ["admin","otherRight"] AS usersRights
MATCH path=allShortestPaths((n1:Node1{id:1})-[*..4]-(n2:Node3{id:3}))
WHERE
ANY (rel IN relationships(path) WHERE ANY(r IN rel.rights WHERE r IN usersRights)) AND
ANY (node IN nodes(path) WHERE ANY(r IN node.rights WHERE r IN usersRights))
RETURN path;
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