[英]Finding intersected rows in different columns and label them
我正在寻找有关如何正确标记数据框中相交行的解决方案。
这样的
df = data.frame(id=c("good","bad","ugly","dirty","clean","frenzy"),di=c("good",2,"good","dirty",4,"ugly"))
> df
id di
1 good good
2 bad 2
3 ugly good
4 dirty dirty
5 clean 4
6 frenzy ugly
我想创建列名match
,如果存在常见的相交行值,则将它们标记为intersected
否则为no.intersect
。
我试过了
df%>%
mutate(match=ifelse(isTRUE(intersect(id,di)),"intersected","no.intersect"))
它输出
id di match
1 good good no.intersect
2 bad 2 no.intersect
3 ugly good no.intersect
4 dirty dirty no.intersect
5 clean 4 no.intersect
6 frenzy ugly no.intersect
尽管第1行和第4行存在相交。
library(dplyr)
# example dataframe
# (non factor variables)
df = data.frame(id=c("good","bad","ugly","dirty","clean","frenzy"),
di=c("good",2,"good","dirty",4,"ugly"),
stringsAsFactors = F)
# check equaity of values at each row
df %>% mutate(match = ifelse(id == di, "intersected", "no.intersect"))
# id di match
# 1 good good intersected
# 2 bad 2 no.intersect
# 3 ugly good no.intersect
# 4 dirty dirty intersected
# 5 clean 4 no.intersect
# 6 frenzy ugly no.intersect
另外,如果要使用intersect
,可以像这样使用它:
df %>%
rowwise() %>%
mutate(match = ifelse(length(intersect(id,di)) > 0, "intersected", "no.intersect")) %>%
ungroup()
# # A tibble: 6 x 3
# id di match
# <chr> <chr> <chr>
# 1 good good intersected
# 2 bad 2 no.intersect
# 3 ugly good no.intersect
# 4 dirty dirty intersected
# 5 clean 4 no.intersect
# 6 frenzy ugly no.intersect
因为intersect
不是向量化的(所以您需要rowwise
),并且它不返回TRUE或FALSE(所以您不能使用isTRUE
)。 如果有匹配项,它将返回实际值;否则,将不返回任何值。
如果您要比较id和di之间的相等性,请尝试:
df %>% mutate(match = ifelse(id == di, "intersected", "no.intersect"))
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