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我如何接受用户的是/否输入,如果他们选择否,则继续通知他们

[英]How do I accept yes/no input from user and continue notifying them if they select no

我希望接受用户输入的是/否,如果用户输入是,则代码将继续运行可用的代码,如果用户输入否,则代码将再次通知用户,并且直到用户最终输入“是”后代码才会运行

这是简短的介绍:

# Here is part1 of code


a = input('Have you finished operation?(Y/N)')

if a.lower()  == {'yes','y' }
    # user input 'y', run part2 code

if a.lower() == {'no', 'n'}
    # user input no
    # code should notifying user again "'Have you finished operation?(Y/N)'"  
    # part2 code will run until user finally input 'y'

if a.lower() !={'yes','y', 'no', 'n'}:
    # user input other words
    # code should notifying user again "'Have you finished operation?(Y/N)'" 


# here is part2 of code

您对如何解决此问题有任何想法,如果您能提供一些建议,我将不胜感激

更新资料

这是我正在练习的代码

yes = {'yes','y',}
no = {'no','n'}

print(1)
print(2)
while True:
a = input('Have you create ''manually_selected_stopwords.txt'' ???(Y/N)''')
if a.lower().split() == yes:
    break
if a.lower().split() == no:
    continue

print(3)
print(4)  

当我运行它时,它显示如下,当我第一次尝试输入“ n”然后输入“ y”时,即使我键入“ y”,它也将始终通知我,并且不会打印3和4

1
2
Have you create manually_selected_stopwords.txt ???(Y/N)>? n
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)>? y
Have you create manually_selected_stopwords.txt ???(Y/N)

您的某些测试是不必要的。 如果您输入“ no”与输入“果酱”,您将得到相同的结果。

# Here is part1 of code

while True:
    # Calling `.lower()` here so we don't keep calling it
    a = input('Have you finished operation?(Y/N)').lower()

    if a == 'yes' or a == 'y':
        # user input 'y', run part2 code
        break


# here is part2 of code
print('part 2')

编辑:

如果要使用set而不是or则可以执行以下操作:

if a in {'yes', 'y'}:

您正在将input() (一个字符串)的结果与一set相等的字符串进行比较。 他们从不平等。

您可以使用in检查输入是否在集合中:

链接骗局要求用户输入直到他们给出有效响应后才可解决您的问题:

# do part one
yes = {"y","yes"}
no = {"n","no"}

print("Doing part 1")
while True:
    try:
        done = input("Done yet? [yes/no]")
    except EOFError:
        print("Sorry, I didn't understand that.")
        continue

    if done.strip().lower() in yes:
        break # leave while
    elif done.strip().lower() in no:
        # do part one again
        print("Doing part 1")
        pass
    else:    
        # neither yes nor no, back to question
        print("Sorry, I didn't understand that.")

print("Doing part 2")

输出:

Doing part 1
Done yet? [yes/no]  # adsgfsa
Sorry, I did not understand that.
Done yet? [yes/no]  # sdgsdfg
Sorry, I did not understand that.
Done yet? [yes/no]  # 23452345
Sorry, I did not understand that.
Done yet? [yes/no]  # sdfgdsfg
Sorry, I did not understand that.
Done yet? [yes/no]  # no
Doing part 1
Done yet? [yes/no]  # yes
Doing part 2

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