[英]SQLAlchemy reference a subquery from a case expression
我有一个hybrid_property,它根据一对多关系进行的一些计算返回一个字符串。
hybrid_property表达式的原始sql是:这是原始sql:
SELECT
CASE
WHEN s.quantity_received = 0 THEN "unreceived"
WHEN s.dif = 0.0 THEN "received"
WHEN s.dif > 0.0 THEN "partially_received"
WHEN s.dif < 0.0 THEN "over_received"
END as status
FROM (
SELECT li.quantity_received, sum(li.quantity - li.received) as 'dif'
FROM line_items as li
WHERE li.o_id = xxx
) as s
模型
class LineItem(BaseModel):
__table__ = Table('line_items', autoload=True)
order = relationship("Order", backreef="line_itms", primaryjoin="Order.id == foregin(LineItem.o_id)")
class Order(BaseModel):
__table__ = Table('orders', autoload=True)
@hybrid_property
def status(self):
qty_received, qty_ordered = 0, 0
for li in self.line_items:
if li.status != "cancelled":
qty_ordered += li.quantity
qty_received += li.quantity_received
if qty_received == 0:
status = "unreceived"
elif qty_received == qty_ordered:
status = "received"
elif qty_received < qty_ordered:
status = "partially_received"
elif qty_received > qty_ordered:
status = "over_received"
return status
@status.expression
def status(cls):
line_items_calc = select([LineItem.quantity_received,
func.sum(LineItem.quantity - LineItem.quantity_received).label('dif')]) \
.where(and_(LineItem.o_id == Order.id,
or_(LineItem.fulfillment_status != "cancelled",
LineItem.fulfillment_status == None))) \
.alias()
qq = select([
case([
(qs.c.quantity_received == 0, "unreceived"),
(qs.c.dif == 0, "received"),
(qs.c.dif > 0, "partially_received"),
(qs.c.dif < 0, "over_received")]
)]) \
.select_from(line_items_calc) \
.as_scalar()
return qq
我有2个订单,订单项为o1和o2:
LineItem(o_id=o1.id, quantity=1, quantity_received=1)
LineItem(o_id=o2.id, quantity=1, quantity_received=0)
LineItem(o_id=o2.id, quantity=2, quantity_received=1)
Order1的状态应为“已接收”,Order2的状态应为“ partially_received”。
但是,当我查询“ received”时,我什么也没有,而当查询“ partially_received”时,我得到2个结果,而不是一个。
看来它没有按Order.id过滤LineItems,因此它使用all来计算状态(因为total_qty为4且接收到的总数为2,这将给出“ partially_received”)
Order.query().filter(Order.status == 'received').all() # returns []
Order.query().filter(Order.status == 'partially_received').all() # returns [Order1, Order2]
如果将.correlate_except(LineItem)
添加到line_items_calc查询中,则会出现以下错误:
OperationalError:(_mysql_exceptions.OperationalError)(1054,“'where子句'中的未知列'orders.id'”“)[SQL:u'SELECT count(*)AS count_1 \\ nFROM(SELECT * \\ nFROM订单\\ nWHEREorders.account_id =%s AND(当(a_3.quantity_received =%s时选择情况)THEN%s当(a_3.dif =%s)THEN%s当(a_3.dif>%s)THEN%s当(a_3.dif <% s)THEN%s END as a_2 \\ nFROM(SELECT line_items.quantity_received AS quantity_received,sum(line_items.quantity - line_items.quantity_received)AS dif \\ nFROM line_items \\ nWHERE line_items.o_id = orders.id AND(line_items.fulfillment_status!=% s OR line_items.fulfillment_status IS NULL))AS a_3)=%s)AS a_1'] [参数:(1L,0,'未接收',0,'已接收',0,'部分接收',0,'超接收', '已取消',u'over_received')]
似乎您正在尝试将表达式与最外面的查询相关联,但是事实证明,当前的嵌套子查询方法在MySQL中不可行,因为与其他某些查询相比,它根本不允许FROM子句中的相关子查询根本不允许与以前的FROM列表项关联的数据库,除非使用LATERAL。
另一方面,嵌套的子查询是多余的,因为您可以在SELECT列表的CASE表达式中使用聚合,但是在当前的子查询中,您会混合使用非聚合和聚合表达式:
SELECT li.quantity_received, sum(li.quantity - li.received) as 'dif'
这很可能不是您想要的。 其他一些数据库甚至不允许执行这样的查询,但是如果禁用了li.quantity_received
,MySQL会默默地从组中未指定的行中选择li.quantity_received的值。 默认情况下,在5.7.5及更高版本中已启用该功能,您应该考虑启用它。 查看您的混合资产的另一半,您似乎也有可能要收取已接收数量的总和。
以下是状态表达式的一个版本,可以满足您在问题中介绍的两个测试用例:
@status.expression
def status(cls):
qty_received = func.coalesce(func.sum(LineItem.quantity_received), 0)
qty_ordered = func.coalesce(func.sum(LineItem.quantity), 0)
return select([case([
(qty_received == 0, "unreceived"),
(qty_received == qty_ordered, "received"),
(qty_received < qty_ordered, "partially_received"),
(qty_received > qty_ordered, "over_received")])]).\
where(and_(func.coalesce(LineItem.fulfillment_status, "") != "cancelled",
LineItem.o_id == cls.id)).\
correlate_except(LineItem).\
as_scalar()
我相信它比您的原始方法更能代表Python方面的方法。 请注意使用COALESCE进行NULL处理。
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