下标超出范围错误，指定数组循环的范围

Question

我的下标超出范围错误。

数组循环的范围一定存在问题，但是我感觉范围已声明，并且我要引用的对应的min和max应该在各自数组中的相同位置。

我尝试了Redim（但可能不正确），并明确指定了数组的尺寸（1到36），但又一次可能不正确。

下标超出范围错误发生在For j = MinAllocation(i) To MaxAllocation(i) 。

'declare variables
Dim Sharpe As Variant
Dim CurrentAllocation As Variant
Dim MaxAllocation As Variant
Dim MinAllocation As Variant
Dim TrialAllocation As Variant
Dim BestAllocation As Variant


inc = Sheet1.Range("B59").Value

'populate variables
CurrentAllocation = Sheet1.Range("S2:S37").Value
MaxAllocation = Sheet1.Range("N2:N37").Value
MinAllocation = Sheet1.Range("P2:P37").Value
TrialAllocation = Sheet1.Range("G2:G37").Value

'Populate trial range with current allocation and populate current Sharpe Ratio
Sheet1.Range("G2:G37").Value = CurrentAllocation
Sharpe = Sheet1.Range("B53").Value

'loop through each cell in the array
Dim i As Long
Dim j As Long


For i = LBound(TrialAllocation) To UBound(TrialAllocation)


   'loop through each possible integer in current cell from corresponding minimum to corresponding maximum
    For j = MinAllocation(i) To MaxAllocation(i) Step inc
    TrialAllocation(i) = j

    'check the total of the trial array and populate worksheet with trial data if the total of the array equals 100 and update timer
    Total = WorksheetFunction.Sum(TrialAllocation)


    If Total = 100 Then
    Sheet1.Range("G2:G37").Value = TrialAllocation

    'Determine how many seconds code took to run
    SecondsElapsed = Round(Timer - StartTime, 2)
    Sheet1.Range("Z42").Value = (SecondsElapsed / 86400)

    'store the trial array if the Sharpe Ratio is greater than the previous highest Sharpe Ratio and further constraints are met (B57 = 0)
    If Sheet1.Range("B53").Value > Sharpe And Sheet1.Range("B57").Value = 0 
    Then
    Sharpe = Sheet1.Range("B53").Value
    BestAllocation = Sheet1.Range("g2:g37").Value

    End If
    End If

    Next Step inc
Next

Answer 1

当您采用多个连续像元的范围的Value属性时，将获得一个二维数组。 如果在监视窗口中检查MinAllocation ，您将看到类似“ Variant / Variant（1到MinAllocation到1）”的内容。

要从2D数组获取特定值，您需要为数组的两个维度指定下标。 因此，对于其他数组， MinAllocation(i)将变为MinAllocation(i, 1) ，依此类推。

LBound和UBound函数可以使用参数来指定要检查的维，但是如果省略此维，则会检查指定数组的第一个维。 这就是为什么对TrialAllocation的边界检查没有失败并且似乎产生了合理的值的原因