下標超出范圍錯誤，指定數組循環的范圍

Question

我的下標超出范圍錯誤。

數組循環的范圍一定存在問題，但是我感覺范圍已聲明，並且我要引用的對應的min和max應該在各自數組中的相同位置。

我嘗試了Redim（但可能不正確），並明確指定了數組的尺寸（1到36），但又一次可能不正確。

下標超出范圍錯誤發生在For j = MinAllocation(i) To MaxAllocation(i) 。

'declare variables
Dim Sharpe As Variant
Dim CurrentAllocation As Variant
Dim MaxAllocation As Variant
Dim MinAllocation As Variant
Dim TrialAllocation As Variant
Dim BestAllocation As Variant


inc = Sheet1.Range("B59").Value

'populate variables
CurrentAllocation = Sheet1.Range("S2:S37").Value
MaxAllocation = Sheet1.Range("N2:N37").Value
MinAllocation = Sheet1.Range("P2:P37").Value
TrialAllocation = Sheet1.Range("G2:G37").Value

'Populate trial range with current allocation and populate current Sharpe Ratio
Sheet1.Range("G2:G37").Value = CurrentAllocation
Sharpe = Sheet1.Range("B53").Value

'loop through each cell in the array
Dim i As Long
Dim j As Long


For i = LBound(TrialAllocation) To UBound(TrialAllocation)


   'loop through each possible integer in current cell from corresponding minimum to corresponding maximum
    For j = MinAllocation(i) To MaxAllocation(i) Step inc
    TrialAllocation(i) = j

    'check the total of the trial array and populate worksheet with trial data if the total of the array equals 100 and update timer
    Total = WorksheetFunction.Sum(TrialAllocation)


    If Total = 100 Then
    Sheet1.Range("G2:G37").Value = TrialAllocation

    'Determine how many seconds code took to run
    SecondsElapsed = Round(Timer - StartTime, 2)
    Sheet1.Range("Z42").Value = (SecondsElapsed / 86400)

    'store the trial array if the Sharpe Ratio is greater than the previous highest Sharpe Ratio and further constraints are met (B57 = 0)
    If Sheet1.Range("B53").Value > Sharpe And Sheet1.Range("B57").Value = 0 
    Then
    Sharpe = Sheet1.Range("B53").Value
    BestAllocation = Sheet1.Range("g2:g37").Value

    End If
    End If

    Next Step inc
Next

Answer 1

當您采用多個連續像元的范圍的Value屬性時，將獲得一個二維數組。 如果在監視窗口中檢查MinAllocation ，您將看到類似“ Variant / Variant（1到MinAllocation到1）”的內容。

要從2D數組獲取特定值，您需要為數組的兩個維度指定下標。 因此，對於其他數組， MinAllocation(i)將變為MinAllocation(i, 1) ，依此類推。

LBound和UBound函數可以使用參數來指定要檢查的維，但是如果省略此維，則會檢查指定數組的第一個維。 這就是為什么對TrialAllocation的邊界檢查沒有失敗並且似乎產生了合理的值的原因