Python列表列表，删除重复项

Question

尝试删除列表列表中的重复项并打印不重复的列表。

原始清单

a = [['country',['America_1','America_2','America_3','America_4','England_5','England_6'],['apple_1_more','orange_1_more']],['country',['Brazil_2','Brazil_3','Brazil_1','Brazil_4','Mexico_1','Mexico_3','Mexico_2'],['grapes_1_less','banana_1_more']]]

寻找输出：

[['country', ['America', 'England'], ['orange_more', 'apple_more']], ['country', ['Mexico', 'Brazil'], ['grapes_less', 'banana_more']]]

但得到：

[['country', ['America', 'England'], ['orange_more', 'apple_more']], ['country', ['America', 'England', 'Mexico', 'Brazil'], ['orange_more', 'grapes_less', 'banana_more', 'apple_more']]]

码：：

 a = [['country',['America_1','America_2','America_3','America_4','England_5','England_6'],['apple_1_more','orange_1_more']],['country',['Brazil_2','Brazil_3','Brazil_1','Brazil_4','Mexico_1','Mexico_3','Mexico_2'],['grapes_1_less','banana_1_more']]]
aa ={}
aaa=[]
aaaa=[]
aaaaa=[]
for i in a:
    for j in i[1]:
        j=j.split('_',1)[0]
        aaa.append(j)
    for k in i[2]:
        k=k.split('_',2)[0]+'_'+k.split('_',2)[2]
        aaaa.append(k)
    aa['country'] = [i[0],list(set(aaa)),list(set(aaaa))]
    aaaaa.append(aa['country'])
print (aaaaa)

Answer 1

使用列表推导，将每个子列表中的第二项与set() ：

a = [['country',['America','America','America','America','England','England']],['country',['Brazil','Brazil','Brazil','Brazil','Mexico','Mexico','Mexico']]]

a = [[i, list(set(j))] for i, j in a]
print(a)

输出：

[['country', ['England', 'America']], ['country', ['Brazil', 'Mexico']]]

由于集合是无序的，因此这可能不会保留内部列表的顺序，因此您可能需要考虑这一点。

Answer 2

您可以尝试以下方法：

a = [['country',['America','America','America','America','England','England']],['country',['Brazil','Brazil','Brazil','Brazil','Mexico','Mexico','Mexico']]]



print(list(map(lambda x:[x[0],list(set(x[1:][0]))],a)))

输出：

[['country', ['England', 'America']], ['country', ['Mexico', 'Brazil']]]

您的变量名称非常混乱，仍然尝试了新方法，您可以尝试以下方法：

a = [['country',['America_1','America_2','America_3','America_4','England_5','England_6'],['apple_1_more','orange_1_more']],['country',['Brazil_2','Brazil_3','Brazil_1','Brazil_4','Mexico_1','Mexico_3','Mexico_2'],['grapes_1_less','banana_1_more']]]


final_data=[]
for i in a:
    sub_data=[]

    for j in i[1:]:
        d = {}

        for m in j:
            data=m.split('_')[0]
            d[data]=data

        sub_data.append(list(d.keys()))
    final_data.append(['country',*sub_data])
print(final_data)

输出：

[['country', ['America', 'England'], ['orange', 'apple']], ['country', ['Brazil', 'Mexico'], ['banana', 'grapes']]]

如果您的数据格式总是这样，则可以尝试以下操作：

更新

a = [['country',['America_1','America_2','America_3','America_4','England_5','England_6'],['apple_1_more','orange_1_more']],['country',['Brazil_2','Brazil_3','Brazil_1','Brazil_4','Mexico_1','Mexico_3','Mexico_2'],['grapes_1_less','banana_1_more']]]


final_data=[]
for i in a:
    sub_data=[]
    sub_extra=[]

    for j in i[1:2]:
        sub_extra.append(i[2])
        d = {}

        for m in j:
            data=m.split('_')[0]
            d[data]=data

        sub_data.extend([list(d.keys()),*sub_extra])
    final_data.append(['country',*sub_data])
print(final_data)

输出：

[['country', ['America', 'England'], ['apple_1_more', 'orange_1_more']], ['country', ['Mexico', 'Brazil'], ['grapes_1_less', 'banana_1_more']]]

Answer 3

使用此递归函数可删除多级数组中的重复项：

def dup(input_):
    if isinstance(input_, list):
        try:
            input_ = list(set([i.split('_')[0] if not isinstance(i, list) else i for i in input_]))
        except TypeError:
            pass
        for child in input_:
            input_[input_.index(child)] = dup(child)

    return input_

Answer 4

这就是我要做的。

country_list1 = [a[0[0]]]
country_list2 = [a[1[0]]]
duplicates = [country for country in country_list1 in country_list2]
non_duplicates = [country for country in country_list1 not in country_list2]

这将为您提供重复的名称和非重复的名称这是考虑到两个名称中的名称区分大小写