[英]GROUP on one column and aggregate counts based on distinct values in another column
[英]How can I group/aggregate values correlated to 2 distinct values as one?
因此,在数据库中,“ value_type”列中存在一个可以互换的值。 当我汇总时,我希望能够将两个值(A和B)加总/汇总在一起,但不能对其他值(C)加总/汇总? 一些样本数据如下:
Value_ID Value_Tx Value_Type
1 5 A
2 2 A
3 7 B
4 5 C
5 3 C
6 1 D
7 7 F
我想要的结果:
Sum Value_Type
14 A | B
8 C
1 D
7 F
我知道总的来说,我会这样做:
select sum(value)tx, value_type
from table
group by value_type;
提前致谢。
用例表达式为group by
。
SELECT SUM(value_tx),
CASE
WHEN value_type IN ( 'A', 'B' ) THEN 'A | B '
ELSE value_type
END
FROM t
GROUP BY CASE
WHEN value_type IN ( 'A', 'B' ) THEN 'A | B '
ELSE value_type
END
ORDER BY 2;
select sum(value)tx, 'A | B' value_type
from table where value_type in ('A','B')
union all
select sum(value)tx, value_type
from table where value_type not in ('A','B')
group by value_type;
简单的方法,希望对您有所帮助:)
我只在MySQL中尝试过查询
select sum(value_tx),
case
when value_type IN ('A', 'B') THEN 'A | B'
else value_type
end as valtype
from table
group by valtype
如何动态设置组的示例:
WITH test_data AS
(
SELECT 1 val_id, 5 val_tx, 'A' val_typ FROM dual
UNION ALL
SELECT 2, 2, 'A' FROM dual
UNION ALL
SELECT 3, 7, 'B' FROM dual
UNION ALL
SELECT 4, 5, 'C' FROM dual
UNION ALL
SELECT 5, 3, 'C' FROM dual
UNION ALL
SELECT 6, 1, 'D' FROM dual
UNION ALL
SELECT 7, 7, 'F' FROM dual
)
SELECT break_group, SUM(val_tx) total_tx, value_type FROM
(
SELECT val_id, val_tx, val_typ
, CASE WHEN dense_rnk IN (1, 2) THEN 1 ELSE (dense_rnk-1) END break_group
, CASE WHEN dense_rnk IN (1, 2) THEN 'A|B' ELSE val_typ END value_type
FROM
(
SELECT val_id, val_tx, val_typ
, DENSE_RANK() OVER (ORDER BY val_typ) dense_rnk
FROM test_data
)
)
GROUP BY break_group, value_type
ORDER BY break_group
/
输出:
BREAK_GROUP TOTAL_TX VALUE_TYPE
-----------------------------------
1 14 A|B
2 8 C
3 1 D
4 7 F
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