[英]GROUP on one column and aggregate counts based on distinct values in another column
[英]How can I group/aggregate values correlated to 2 distinct values as one?
因此,在數據庫中,“ value_type”列中存在一個可以互換的值。 當我匯總時,我希望能夠將兩個值(A和B)加總/匯總在一起,但不能對其他值(C)加總/匯總? 一些樣本數據如下:
Value_ID Value_Tx Value_Type
1 5 A
2 2 A
3 7 B
4 5 C
5 3 C
6 1 D
7 7 F
我想要的結果:
Sum Value_Type
14 A | B
8 C
1 D
7 F
我知道總的來說,我會這樣做:
select sum(value)tx, value_type
from table
group by value_type;
提前致謝。
用例表達式為group by
。
SELECT SUM(value_tx),
CASE
WHEN value_type IN ( 'A', 'B' ) THEN 'A | B '
ELSE value_type
END
FROM t
GROUP BY CASE
WHEN value_type IN ( 'A', 'B' ) THEN 'A | B '
ELSE value_type
END
ORDER BY 2;
select sum(value)tx, 'A | B' value_type
from table where value_type in ('A','B')
union all
select sum(value)tx, value_type
from table where value_type not in ('A','B')
group by value_type;
簡單的方法,希望對您有所幫助:)
我只在MySQL中嘗試過查詢
select sum(value_tx),
case
when value_type IN ('A', 'B') THEN 'A | B'
else value_type
end as valtype
from table
group by valtype
如何動態設置組的示例:
WITH test_data AS
(
SELECT 1 val_id, 5 val_tx, 'A' val_typ FROM dual
UNION ALL
SELECT 2, 2, 'A' FROM dual
UNION ALL
SELECT 3, 7, 'B' FROM dual
UNION ALL
SELECT 4, 5, 'C' FROM dual
UNION ALL
SELECT 5, 3, 'C' FROM dual
UNION ALL
SELECT 6, 1, 'D' FROM dual
UNION ALL
SELECT 7, 7, 'F' FROM dual
)
SELECT break_group, SUM(val_tx) total_tx, value_type FROM
(
SELECT val_id, val_tx, val_typ
, CASE WHEN dense_rnk IN (1, 2) THEN 1 ELSE (dense_rnk-1) END break_group
, CASE WHEN dense_rnk IN (1, 2) THEN 'A|B' ELSE val_typ END value_type
FROM
(
SELECT val_id, val_tx, val_typ
, DENSE_RANK() OVER (ORDER BY val_typ) dense_rnk
FROM test_data
)
)
GROUP BY break_group, value_type
ORDER BY break_group
/
輸出:
BREAK_GROUP TOTAL_TX VALUE_TYPE
-----------------------------------
1 14 A|B
2 8 C
3 1 D
4 7 F
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.