[英]Recursively accessing paths and values of a nested dictionary
在Python 2.7中,如何动态访问和打印嵌套字典的键和值? 这是一个荒谬的例子: https : //jsoneditoronline.org/? id = da7a486dc2e24bf8b94add9f04c71b4d
通常情况下,我会这样做:
import json
json_sample = 'sample_dict.json'
json_file = open(json_sample, 'r')
json_data = json.load(json_file)
items = json_data['sample_dict']
for item in items:
dict_id = item['dict_id']
person = item['person']['person_id']
family = item['family']['members']
print dict_id
print person
print family
我可以像这样硬编码,它会给我理想的结果,但我如何动态访问每个键和值,以便:
dict_id
, person['person_id']
, person['name']
, family['members']['father']
) 最终结果应该是CSV文件。
您可以使用递归访问者/生成器返回叶子的所有路径/值对:
def visit_dict(d, path=[]):
for k, v in d.items():
if not isinstance(v, dict):
yield path + [k], v
else:
yield from visit_dict(v, path + [k])
(如果使用Python <3.4,则使用适当的等效项替换...的yield from ...
)
获得钥匙:
>>> ','.join('/'.join(k) for k, v in visit_dict(json_data['sample_dict'][0]))
'dict_id,person/person_id,person/name,person/age,family/person_id,family/members/father,family/members/mother,family/members/son,family/family_id,items_id,furniture/type,furniture/color,furniture/size,furniture/purchases'
和价值观:
>>> ','.join(str(v) for k, v in visit_dict(json_data['sample_dict'][0]))
'5,15,Martin,18,20,Jose,Maddie,Jerry,2,None,Chair,Brown,Large,[]'
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