在文件夹中的每个文件上执行的Powershell脚本？

Question

我目前有一个powershell脚本，该脚本输出有关作为参数传入的文件的一些信息。

执行脚本的命令，它是这样完成的：

.\myscript.ps1 -accessitem C:\folder

我想将脚本应用于驱动器C:上的所有文件和文件夹，是否可能for loop列出所有文件，并将路径作为脚本的参数传递？

剧本：

[CmdletBinding()]
Param (
    [Parameter(Mandatory=$True,Position=0)]
    [String]$AccessItem
)
$ErrorActionPreference = "SilentlyContinue"
If ($Error) {
    $Error.Clear()
}
$RepPath = Split-Path -Parent $MyInvocation.MyCommand.Definition
$RepPath = $RepPath.Trim()
$str = $AccessItem -replace ':',''
$str = $AccessItem -replace '/','.'

$FinalReport = "$RepPath\"+$str+".csv"
$ReportFile1 = "$RepPath\NTFSPermission_Report.txt"

If (!(Test-Path $AccessItem)) {
    Write-Host
    Write-Host "`t Item $AccessItem Not Found." -ForegroundColor "Yellow"
    Write-Host
}
Else {
    If (Test-Path $FinalReport) {
        Remove-Item $FinalReport
    }
    If (Test-Path $ReportFile1) {
        Remove-Item $ReportFile1
    }
    Write-Host
    Write-Host "`t Working. Please wait ... " -ForegroundColor "Yellow"
    Write-Host
    ## -- Create The Report File
    $ObjFSO = New-Object -ComObject Scripting.FileSystemObject
    $ObjFile = $ObjFSO.CreateTextFile($ReportFile1, $True)
    $ObjFile.Write("NTFS Permission Set On -- $AccessItem `r`n")
    $ObjFile.Close()
    $ObjFile = $ObjFSO.CreateTextFile($FinalReport, $True)
    $ObjFile.Close()
    [System.Runtime.Interopservices.Marshal]::ReleaseComObject($ObjFSO) | Out-Null
    Remove-Variable ObjFile
    Remove-Variable ObjFSO
    If((Get-Item $AccessItem).PSIsContainer -EQ $True) {
        $Result = "ItemType -- Folder"
    }
    Else {
        $Result = "ItemType -- File"
    }
    $DT = Get-Date -Format F
    Add-Content $ReportFile1 -Value ("Report Created As On $DT")
    Add-Content $ReportFile1 "=================================================================="
    $Owner = (Get-Item -LiteralPath $AccessItem).GetAccessControl() | Select Owner
    $Owner = $($Owner.Owner)
    $Result = "$Result `t Owner -- $Owner"
    Add-Content $ReportFile1 "$Result `n"
    (Get-Item -LiteralPath $AccessItem).GetAccessControl() | Select * -Expand Access | Select IdentityReference, FileSystemRights, AccessControlType, IsInherited, InheritanceFlags, PropagationFlags | Export-CSV -Path "$RepPath\NTFSPermission_Report2.csv" -NoTypeInformation
    Add-Content $FinalReport -Value (Get-Content $ReportFile1)
    Add-Content $FinalReport -Value (Get-Content "$RepPath\NTFSPermission_Report2.csv")
    Remove-Item $ReportFile1
    Remove-Item "$RepPath\NTFSPermission_Report2.csv"
    Invoke-Item $FinalReport
}
If ($Error) {
    $Error.Clear()
}

我宁愿使用外部命令来执行此操作，因为不应更改脚本的工作方式，该脚本用于单个文件测试。

Answer 1

有两种方法可以做到这一点：

1. 在脚本中添加-Recurse标志
2. 在每个目录上运行脚本

我使用选项二，因为脚本看起来足够复杂，我不想去碰它。

$path_to_script = "C:\path\to\myscript.ps1"
$start_directory  = "C:\folder"

# Call Script on Parent Directory
& "$path_to_script" -AccessItem "$start_directory"

# Call Script on any Child Directories within the "$start_directory"
foreach($child in (ls "$start_directory" -Recurse  -Directory))
{
    $path = $child.FullName
    & "$path_to_script" -AccessItem "$path"
}

基本上，我在父目录和父目录中的所有子目录上调用脚本。