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[英]Upload a base64 string(Image Data) to S3 server in Python using Boto3 and get URL in return
[英]s3 upload from base64 using Lambda
我有以下代码:
import base64
imgdata = base64.b64decode(new_string)
filename = 'image.jpg' # I assume you have a way of picking unique filenames
with open(filename, 'wb') as f:
f.write(imgdata)
它将文件另存为jpg,我可以打开它。
如何将其上传到s3存储桶或任何其他服务,并返回URL安全性不是问题。
我试过了
try:
convertedFileString = fstring.replace('-', '+').replace('_','/').replace(',','=')
imgdata = base64.b64decode(new_string)
# I assume you have a way of picking unique filenames
with open(filename, 'wb') as f:
s3 = boto3.resource('s3')
bucket = s3.Bucket('ag-grid')
bucket.put_object(Key=filename, Body=f)
except Exception as e:
return {
'statusCode': 500,
'body': str(e)
}
因此,我不确定是否了解您的问题。
我使用下面的代码进行上传,并且可以正常工作。
# Filename
new_name = '{}_{}_{}_{}_{}_{}x{}.{}'.format(cid, uid, id_service_order, id_question, uuid.uuid4(), 0, 0,
fileExtension) # type: str
key = "{}".format(new_name)
# Let's use Amazon S3
s3 = boto3.client("s3",
aws_access_key_id=aws_config.aws_access_key_id,
aws_secret_access_key=aws_config.aws_secret_access_key,
region_name=aws_config.aws_s3_region,
config=Config(signature_version='s3v4'))
dec = base64.b64decode(img_base64)
rs = s3.put_object(
Bucket=aws_config.aws_s3_bucket,
Key=key,
ContentType=fileType,
Body=dec,
ACL='public-read'
)
print(rs)
print(new_name)
这对您有帮助吗?
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