[英]Python Beautiful Soup Parse First Href in Each Div
给出以下代码:
# import the module
import bs4 as bs
import urllib.request
import re
masterURL = 'http://www.metrolyrics.com/top100.html'
sauce = urllib.request.urlopen(masterURL).read()
soup = bs.BeautifulSoup(sauce,'lxml')
for div in soup.findAll('ul', {'class': 'song-list'}):
for span in div:
for link in span:
for a in link:
print(a)
我可以解析多个div,结果如下:
我的问题是,没有获得div的全部内容,我如何只返回突出显示的部分Href的URL?
尝试这个。 您需要指定正确的class
来获取连接到它的URL。
from bs4 import BeautifulSoup
import urllib.request
masterURL = 'http://www.metrolyrics.com/top100.html'
sauce = urllib.request.urlopen(masterURL).read()
soup = BeautifulSoup(sauce,'lxml')
for div in soup.find_all(class_='subtitle'):
print(div.get("href"))
输出:
http://www.metrolyrics.com/charles-goose-lyrics.html
http://www.metrolyrics.com/param-singh-lyrics.html
http://www.metrolyrics.com/westlife-lyrics.html
http://www.metrolyrics.com/luis-fonsi-lyrics.html
http://www.metrolyrics.com/grease-lyrics.html
http://www.metrolyrics.com/shanti-dope-lyrics.html
等等 - -
if 'href' in a.attrs:
a.attrs['href']
这将为您提供所需的东西。
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