[英]SQL SELECT MIN value with WHERE statement
我认为您只需要一个相关的子查询:
SELECT p.*
FROM price p
WHERE p.id_quote = 36 AND
p.price = (SELECT MIN(p2.price) FROM price p2 WHERE p2.id_quote = p.id_quote);
请注意,“ quote”条件已移至外部查询。
我喜欢将RANK()用于此类问题:
SELECT id_quote, id_provider, price
FROM
(
SELECT id_quote id_provider, price,
RANK() OVER(PARTITION BY id_quote ORDER BY price ASC) AS rnk
FROM price
) sub
WHERE rnk = 1
You can do it this way if you want:
SELECT TOP 1 id_provider, price FROM price WHERE id_quote=36 ORDER BY price ASC
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