[英]Organizing files into folders based on filename
我正在尝试创建一个程序,以读取pdf文件(例如,files.pdf),按名称将其分离,然后将其移动到其相关的文件夹(基于名称),如下所示:
Files:
house.pdf
house_blue.pdf
road.pdf
Folders:
house = house.pdf, house_blue.pdf
road = road.pdf
现在我的代码:
for f in os.listdir():
file_name, file_ext = os.path.splitext(f)
if len(file_name.split('_')) == 2:
f_name, f_course = file_name.split('_')
elif len(file_name.split('_')) != 2:
f_name = file_name
def movefile (file_name):
new_dir = src + "/" + file_name
for file_name in os.listdir():
if not os.path.exists(new_dir):
os.mkdir(new_dir)
if file_name.startswith(file_name):
shutil.move(src+"/"+file_name, new_dir)
它工作正常,唯一的问题是for语句仅生成最后一个pdf文件,仅创建一个文件夹并将所有文件复制到该文件夹。
有人可以在错误地方帮助我吗?
提前致谢。
编辑:代码工作:
src = (os.getcwd())
for f in os.walk(src):
for f in os.listdir(src):
if os.path.isfile(src): #Checar se possui arquivos dentro da pasta(src).
continue
lfolders = os.listdir(src) #Atribuir na variavel lfolders todos os diretórios na pasta (src).
file_name, file_ext = os.path.splitext(f) #separar nome da extensão (.pdf)
if len(file_name.split('_')) == 2: #se possuir dois nomes (nome e curso)
f_name, f_course = file_name.split('_')
try:
if f_name not in lfolders:
for dirmake in os.listdir(src):
os.makedirs(os.path.join(src, f_name))
elif f_name in lfolders:
shutil.move(f, src+"/"+f_name)
except OSError:
pass
elif len(file_name.split(')')) != 2: #se possuir um nome (nome)
f_name = file_name
try:
if f_name not in lfolders:
for dirmake in os.listdir(src):
os.makedirs(os.path.join(src, f_name))
elif f_name in lfolders:
shutil.move(f, src+"/"+f_name)
except OSError:
pass
如果我理解正确,则需要为循环的每次迭代做一些事情 。
for f in os.listdir():
file_name, file_ext = os.path.splitext(f)
if file_ext == 'pdf':
if len(file_name.split('_')) == 2:
folder, f_course = file_name.split('_')
elif len(file_name.split('_')) != 2:
folder = file_name
print("Ready to move {} into folder {}".format(file_name, folder))
movefile(f, folder) # Call your function, add a parameter for the folder
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