从MySQL收到的Swift中将base64字符串编码为图像

Question

我从mysql接收到base64字符串（存储为blob），并尝试将其编码为：

func loadImage() {
    var request = URLRequest(url: URL(string: URL_IMAGES)!)
    request.httpMethod = "POST"
    let userid = self.defaultValues.integer(forKey: "userid")
    let postString = "userid=\(userid)"
    request.httpBody = postString.data(using: .utf8)
    let task = URLSession.shared.dataTask(with: request) { data, response, error in
        guard let data = data, error == nil else {
            print("error=\(String(describing: error))")
            return
        }

        if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {
            print("statusCode should be 200, but is \(httpStatus.statusCode)")
            print("response = \(String(describing: response))")
        }

        let responseString = String(data: data, encoding: .utf8)
        if let encodedImage = responseString,
            let imageData =  NSData(base64Encoded: encodedImage, options: .ignoreUnknownCharacters),
            let image = UIImage(data: imageData as Data) {
            print(image.size)
        }
    }
    task.resume()
}

php文件如下所示：

<?php
$userid=$_POST["userid"];
$conn = mysqli_connect(connection);
if ($conn->connect_error) {
    die("Connection failed: " . $conn>connect_error);
} 
$sql = "SELECT profilepicture FROM users WHERE id = $userid";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
     while($row = $result->fetch_assoc()) {
         $out[]=$row;
     }
    echo json_encode($out);
} else {
  echo "0 results";
}
?>

编辑2 *这就是我将图像存储到数据库中的方式：

@objc func updateUser(sender: UIButton!) {
    let refreshAlert = UIAlertController(title: "Update profile?", message: "Do you want to update your profile? This will log you out to update the data!", preferredStyle: UIAlertControllerStyle.alert)
    refreshAlert.view.tintColor = UIColor.red
    refreshAlert.addAction(UIAlertAction(title: "Ok", style: .default, handler: { (action: UIAlertAction!) in

        let URL_REQUEST = "request"

        self.messageLbl.text = ""

        var request = URLRequest(url: URL(string: URL_REQUEST)!)
        request.httpMethod = "POST"
        let userid = self.defaultValues.integer(forKey: "userid")
        let password = self.passWordTf.text!
        let email = self.eMailTf.text!
        let image = self.imageView.image!
        guard let pictStr = self.convertImageBase64(image: image) else {
            return
        }
        let postString = "id=\(userid)&password=\(password)&email=\(email)&profilepicture=\(pictStr)"
        request.httpBody = postString.data(using: .utf8)
        let task = URLSession.shared.dataTask(with: request) { data, response, error in
            guard let data = data, error == nil else {
                print("error=\(String(describing: error))")
                return
            }

            if let httpStatus = response as? HTTPURLResponse, httpStatus.statusCode != 200 {
                print("statusCode should be 200, but is \(httpStatus.statusCode)")
                print("response = \(String(describing: response))")
            }

            let responseString = String(data: data, encoding: .utf8)
            print("responseString = \(String(describing: responseString))")
        }
        task.resume()

        if (self.eMailTf.text != self.defaultValues.string(forKey: "useremail")) {
            self.defaultValues.set(self.eMailTf.text, forKey: "useremail")
        }
        self.navigationController?.popViewController(animated: true)
    }))

    refreshAlert.addAction(UIAlertAction(title: "Cancel", style: .default, handler: { (action: UIAlertAction!) in
        print("Handle Cancel Logic here")
    }))

    present(refreshAlert, animated: true, completion: nil)
}

编辑2 *这是编码功能：

func convertImageBase64(image: UIImage) -> String? {
    guard let pictData = UIImagePNGRepresentation(image) else {
        return nil
    }
    let strBase64: String = pictData.base64EncodedString(options: [])
    return strBase64
}

编辑2 *和用于存储的php文件：

<?php
$userid=$_POST["userid"];
$password=$_POST["password"];
$pass = md5($password);
$email=$_POST["email"];
$profilepicture=$_POST["profilepicture"];


$conn = mysqli_connect(connection);

if ($conn->connect_error) {
 die("Connection failed: " . $conn->connect_error);
} 

$sql =("UPDATE users SET password='".$pass."' ,  email='".$email."' , profilepicture='".$profilepicture."' WHERE id=".$userid."");

if ($conn->query($sql) === TRUE) {
    echo "Record updated successfully";
} else {
    echo "Error updating record: " . $conn->error;
}

$conn->close();
?>

这是一个类似的问题这个 ，但即使尝试所有的答案并没有为我工作。 我得到的响应是正确的，但我无法对其进行编码，因为我总是在尝试编码时得到nil：

我也尝试过很多类似的事情：

在Swift中从JSON解码base64_encode图像

编辑1

im接收的字符串具有以下前缀：“ [{\\” profilepicture \\“：\\” iVBORw0KGgoAAAANSUhE ...

是否可以在没有此前缀的情况下转换字符串，或者该前缀甚至与转换字符串都不相关？

编辑2

Answer 1

您的服务器端代码返回JSON数据，其中包含通过fetch_assoc()检索的assoc数组的数组。

我建议您更新服务器端代码，因为它返回除图像数据以外的其他内容，因此最好只发送图像数据。

但是，如果您想按原样使用服务器端代码，则可能需要在loadImage编写如下loadImage ：

    let task = URLSession.shared.dataTask(with: request) { data, response, error in
        guard let data = data, error == nil else {
            print("error=\(error?.localizedDescription ?? "nil")")
            return
        }

        guard let httpResponse = response as? HTTPURLResponse else {
            print("response is not an HTTPURLResponse")
            return
        }
        guard httpResponse.statusCode == 200 else {
            print("statusCode should be 200, but is \(httpResponse.statusCode)")
            print("response = \(httpResponse)")
            return
        }

        do {
            //First decode the response body as JSON
            let json = try JSONSerialization.jsonObject(with: data)
            //The decoded object should be a JSON array containing one JSON object
            guard let arr = json as? [[String: Any]], !arr.isEmpty else {
                print("json is not an array, or is empty")
                return
            }
            //Use only the first record
            let person = arr[0]
            //Retrieve the column value of "profilepicture" in the first record
            guard let encodedImage = person["profilepicture"] as? String else {
                print("NO profilepicture")
                return
            }
            //Decode it into binary data as Base64
            guard let imageData =  Data(base64Encoded: encodedImage, options: .ignoreUnknownCharacters) else {
                print("encodedImage is not a valid Base64")
                return
            }
            //Convert the decoded binary data into an image
            guard let image = UIImage(data: imageData) else {
                print("imageData is in a unsupported format or is not an image")
                return
            }
            print(image.size)
            //Use `image` here...
        } catch {
            print(error)
        }
    }
    task.resume()

您可能需要修改某些部分，但是当我在坏情况下嵌入许多print ，可以轻松找到要修复的地方。