将东距/北距转换为 Lat Lng

Question

我一直在努力在不使用 nuget 包的情况下将北向/东向转换为纬度/经度。 我确定我的 UTM 区域是 30U（英国）。

如何在 C# 中做到这一点？

使用本网站手动完成时。 它提供了正确的值和位置。 东距：426342 北距：505339 纬度/经度应为：54.44277977022131，-1.5953328509040021

我以前在 stackoverflow 上找到了一些代码，但它给了我错误的值。

utmZone = "30U"

  public static LatLng ToLatLon(double utmX, double utmY, string utmZone)
    {
    bool isNorthHemisphere = utmZone.Last() >= 'N';

    var diflat = -0.00066286966871111111111111111111111111;
    var diflon = -0.0003868060578;

    var zone = int.Parse(utmZone.Remove(utmZone.Length - 1));
    var c_sa = 6378137.000000;
    var c_sb = 6356752.314245;
    var e2 = Math.Pow((Math.Pow(c_sa, 2) - Math.Pow(c_sb, 2)), 0.5) / c_sb;
    var e2cuadrada = Math.Pow(e2, 2);
    var c = Math.Pow(c_sa, 2) / c_sb;
    var x = utmX - 500000;
    var y = isNorthHemisphere ? utmY : utmY - 10000000;

    var s = ((zone * 6.0) - 183.0);
    var lat = y / (c_sa * 0.9996);
    var v = (c / Math.Pow(1 + (e2cuadrada * Math.Pow(Math.Cos(lat), 2)), 0.5)) * 0.9996;
    var a = x / v;
    var a1 = Math.Sin(2 * lat);
    var a2 = a1 * Math.Pow((Math.Cos(lat)), 2);
    var j2 = lat + (a1 / 2.0);
    var j4 = ((3 * j2) + a2) / 4.0;
    var j6 = ((5 * j4) + Math.Pow(a2 * (Math.Cos(lat)), 2)) / 3.0;
    var alfa = (3.0 / 4.0) * e2cuadrada;
    var beta = (5.0 / 3.0) * Math.Pow(alfa, 2);
    var gama = (35.0 / 27.0) * Math.Pow(alfa, 3);
    var bm = 0.9996 * c * (lat - alfa * j2 + beta * j4 - gama * j6);
    var b = (y - bm) / v;
    var epsi = ((e2cuadrada * Math.Pow(a, 2)) / 2.0) * Math.Pow((Math.Cos(lat)), 2);
    var eps = a * (1 - (epsi / 3.0));
    var nab = (b * (1 - epsi)) + lat;
    var senoheps = (Math.Exp(eps) - Math.Exp(-eps)) / 2.0;
    var delt = Math.Atan(senoheps / (Math.Cos(nab)));
    var tao = Math.Atan(Math.Cos(delt) * Math.Tan(nab));

    double longitude = ((delt * (180.0 / Math.PI)) + s) + diflon;
    double latitude = ((lat + (1 + e2cuadrada * Math.Pow(Math.Cos(lat), 2) - (3.0 / 2.0) * e2cuadrada * Math.Sin(lat) * Math.Cos(lat) * (tao - lat)) * (tao - lat)) * (180.0 / Math.PI)) + diflat;

    return new LatLng
    {
        Latitude = latitude,
        Longitude = longitude
    };
}

Answer 1

参考以下代码并运行LatLonConversions.ConvertOSToLatLon(426342, 505339)

 public class LatLonConversions { const double a = 6377563.396; const double b = 6356256.91; const double e2 = (a - b) / a; const double n0 = -100000; const double e0 = 400000; const double f0 = 0.999601272; const double phi0 = 0.855211333; const double lambda0 = -0.034906585; const double n = (a - b) / (a + b); static double lat, lng; private LatLonConversions() { } private static double Deg2Rad(double x) { return x * (Math.PI / 180); } private static double Rad2Deg(double x) { return x * (180 / Math.PI); } private static double SinSquared(double x) { return Math.Sin(x) * Math.Sin(x); } private static double TanSquared(double x) { return Math.Tan(x) * Math.Tan(x); } private static double Sec(double x) { return 1.0 / Math.Cos(x); } private static void OSGB36ToWGS84() { var airy1830 = new RefEll(6377563.396, 6356256.909); var a = airy1830.maj; var b = airy1830.min; var eSquared = airy1830.ecc; var phi = Deg2Rad(lat); var lambda = Deg2Rad(lng); var v = a / (Math.Sqrt(1 - eSquared * SinSquared(phi))); var H = 0; // height var x = (v + H) * Math.Cos(phi) * Math.Cos(lambda); var y = (v + H) * Math.Cos(phi) * Math.Sin(lambda); var z = ((1 - eSquared) * v + H) * Math.Sin(phi); var tx = 446.448; var ty = -124.157; var tz = 542.060; var s = -0.0000204894; var rx = Deg2Rad(0.00004172222); var ry = Deg2Rad(0.00006861111); var rz = Deg2Rad(0.00023391666); var xB = tx + (x * (1 + s)) + (-rx * y) + (ry * z); var yB = ty + (rz * x) + (y * (1 + s)) + (-rx * z); var zB = tz + (-ry * x) + (rx * y) + (z * (1 + s)); var wgs84 = new RefEll(6378137.000, 6356752.3141); a = wgs84.maj; b = wgs84.min; eSquared = wgs84.ecc; var lambdaB = Rad2Deg(Math.Atan(yB / xB)); var p = Math.Sqrt((xB * xB) + (yB * yB)); var phiN = Math.Atan(zB / (p * (1 - eSquared))); for (var i = 1; i < 10; i++) { v = a / (Math.Sqrt(1 - eSquared * SinSquared(phiN))); double phiN1 = Math.Atan((zB + (eSquared * v * Math.Sin(phiN))) / p); phiN = phiN1; } var phiB = Rad2Deg(phiN); lat = phiB; lng = lambdaB; } public static LatLon ConvertOSToLatLon(double easting, double northing) { RefEll airy1830 = new RefEll(6377563.396, 6356256.909); double OSGB_F0 = 0.9996012717; double N0 = -100000.0; double E0 = 400000.0; double phi0 = Deg2Rad(49.0); double lambda0 = Deg2Rad(-2.0); double a = airy1830.maj; double b = airy1830.min; double eSquared = airy1830.ecc; double phi = 0.0; double lambda = 0.0; double E = easting; double N = northing; double n = (a - b) / (a + b); double M = 0.0; double phiPrime = ((N - N0) / (a * OSGB_F0)) + phi0; do { M = (b * OSGB_F0) * (((1 + n + ((5.0 / 4.0) * n * n) + ((5.0 / 4.0) * n * n * n)) * (phiPrime - phi0)) - (((3 * n) + (3 * n * n) + ((21.0 / 8.0) * n * n * n)) * Math.Sin(phiPrime - phi0) * Math.Cos(phiPrime + phi0)) + ((((15.0 / 8.0) * n * n) + ((15.0 / 8.0) * n * n * n)) * Math.Sin(2.0 * (phiPrime - phi0)) * Math.Cos(2.0 * (phiPrime + phi0))) - (((35.0 / 24.0) * n * n * n) * Math.Sin(3.0 * (phiPrime - phi0)) * Math.Cos(3.0 * (phiPrime + phi0)))); phiPrime += (N - N0 - M) / (a * OSGB_F0); } while ((N - N0 - M) >= 0.001); var v = a * OSGB_F0 * Math.Pow(1.0 - eSquared * SinSquared(phiPrime), -0.5); var rho = a * OSGB_F0 * (1.0 - eSquared) * Math.Pow(1.0 - eSquared * SinSquared(phiPrime), -1.5); var etaSquared = (v / rho) - 1.0; var VII = Math.Tan(phiPrime) / (2 * rho * v); var VIII = (Math.Tan(phiPrime) / (24.0 * rho * Math.Pow(v, 3.0))) * (5.0 + (3.0 * TanSquared(phiPrime)) + etaSquared - (9.0 * TanSquared(phiPrime) * etaSquared)); var IX = (Math.Tan(phiPrime) / (720.0 * rho * Math.Pow(v, 5.0))) * (61.0 + (90.0 * TanSquared(phiPrime)) + (45.0 * TanSquared(phiPrime) * TanSquared(phiPrime))); var X = Sec(phiPrime) / v; var XI = (Sec(phiPrime) / (6.0 * v * v * v)) * ((v / rho) + (2 * TanSquared(phiPrime))); var XII = (Sec(phiPrime) / (120.0 * Math.Pow(v, 5.0))) * (5.0 + (28.0 * TanSquared(phiPrime)) + (24.0 * TanSquared(phiPrime) * TanSquared(phiPrime))); var XIIA = (Sec(phiPrime) / (5040.0 * Math.Pow(v, 7.0))) * (61.0 + (662.0 * TanSquared(phiPrime)) + (1320.0 * TanSquared(phiPrime) * TanSquared(phiPrime)) + (720.0 * TanSquared(phiPrime) * TanSquared(phiPrime) * TanSquared(phiPrime))); phi = phiPrime - (VII * Math.Pow(E - E0, 2.0)) + (VIII * Math.Pow(E - E0, 4.0)) - (IX * Math.Pow(E - E0, 6.0)); lambda = lambda0 + (X * (E - E0)) - (XI * Math.Pow(E - E0, 3.0)) + (XII * Math.Pow(E - E0, 5.0)) - (XIIA * Math.Pow(E - E0, 7.0)); lat = Rad2Deg(phi); lng = Rad2Deg(lambda); // convert to WGS84 OSGB36ToWGS84(); return new LatLon(lat, lng); } } public class RefEll { public double maj, min, ecc; public RefEll(double major, double minor) { maj = major; min = minor; ecc = ((major * major) - (minor * minor)) / (major * major); } } public class LatLon { public double Latitude; public double Longitude; public LatLon() { Latitude = 0; Longitude = 0; } public LatLon(double lat, double lon) { Latitude = lat; Longitude = lon; } }

Answer 2

我遇到了同样的问题。 最终使用了这个库： https : //github.com/Tronald/CoordinateSharp

此示例将返回以 latlon 十进制表示的确切位置。

UniversalTransverseMercator utm = new UniversalTransverseMercator("T", 30, 581177.3879, 4794824.5279);
Coordinate c = UniversalTransverseMercator.ConvertUTMtoLatLong(utm);
c.FormatOptions.Format = CoordinateFormatType.Decimal;
c.FormatOptions.Round = 7;

Debug.Log($"({c.Latitude}, {c.Longitude})");