[英]How to use Distinct in WHERE clause
我有这个查询来统计员工在一个月内的礼物数。
SELECT DISTINCT
COUNT([Attendance].[Status])
FROM
[HRM].[tbl_EmployeeAttendance] [Attendance], [HRM].[tbl_EmployeeInfo] [Info]
WHERE
[Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In')
AND [Info].[ID] = [Attendance].[EmpCode]
AND [Attendance].[EmpCode] = 266
AND CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'
AND CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
现在有很多员工被标记为两次或三次出勤。 就像一旦雇员离职,他的出勤就被安排成一次外出,而一旦他来就比按时来待。 因此,现在可以算是增加了同一天的出勤次数。 我想获得日期之间的不同日期。
这是示例数据:
2018-04-04 18:12:30 2018-04-04 19:38:12 266 Present
2018-04-04 09:43:01 2018-04-04 09:58:41 266 Present
2018-04-05 16:40:52 2018-04-05 18:40:52 266 Present
2018-04-06 11:35:59 2018-04-06 11:48:49 266 Present
现在它是两次对日期4进行计数,但是应该对它进行一次计数。
DISTINCT
应该在COUNT()
内部
因此,它将是:
SELECT COUNT(DISTINCT [Attendance].[Status]),
COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] AS Date))
. . .
但是,我建议在FROM
子句中使用适当的标准,显式JOIN
语法代替逗号:
SELECT COUNT(DISTINCT [Attendance].[Status]),
COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] AS Date))
FROM [HRM].[tbl_EmployeeAttendance] [Attendance] INNER JOIN
[HRM].[tbl_EmployeeInfo] [Info]
ON [Info].[ID] = [Attendance].[EmpCode]
WHERE [Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In') AND
[Attendance].[EmpCode] = 266 AND
CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'AND
CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
尝试此操作以显示最新日期并执行独特的
SELECT COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] as Date))
FROM [HRM].[tbl_EmployeeAttendance] [Attendance], [HRM].[tbl_EmployeeInfo] [Info]
WHERE [Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In')
AND [Info].[ID] = [Attendance].[EmpCode] AND [Attendance].[EmpCode] = 266
AND CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'
AND CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
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