[英]How to use Distinct in WHERE clause
我有這個查詢來統計員工在一個月內的禮物數。
SELECT DISTINCT
COUNT([Attendance].[Status])
FROM
[HRM].[tbl_EmployeeAttendance] [Attendance], [HRM].[tbl_EmployeeInfo] [Info]
WHERE
[Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In')
AND [Info].[ID] = [Attendance].[EmpCode]
AND [Attendance].[EmpCode] = 266
AND CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'
AND CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
現在有很多員工被標記為兩次或三次出勤。 就像一旦雇員離職,他的出勤就被安排成一次外出,而一旦他來就比按時來待。 因此,現在可以算是增加了同一天的出勤次數。 我想獲得日期之間的不同日期。
這是示例數據:
2018-04-04 18:12:30 2018-04-04 19:38:12 266 Present
2018-04-04 09:43:01 2018-04-04 09:58:41 266 Present
2018-04-05 16:40:52 2018-04-05 18:40:52 266 Present
2018-04-06 11:35:59 2018-04-06 11:48:49 266 Present
現在它是兩次對日期4進行計數,但是應該對它進行一次計數。
DISTINCT
應該在COUNT()
內部
因此,它將是:
SELECT COUNT(DISTINCT [Attendance].[Status]),
COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] AS Date))
. . .
但是,我建議在FROM
子句中使用適當的標准,顯式JOIN
語法代替逗號:
SELECT COUNT(DISTINCT [Attendance].[Status]),
COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] AS Date))
FROM [HRM].[tbl_EmployeeAttendance] [Attendance] INNER JOIN
[HRM].[tbl_EmployeeInfo] [Info]
ON [Info].[ID] = [Attendance].[EmpCode]
WHERE [Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In') AND
[Attendance].[EmpCode] = 266 AND
CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'AND
CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
嘗試此操作以顯示最新日期並執行獨特的
SELECT COUNT(DISTINCT CAST([Attendance].[AttendanceTimeIn] as Date))
FROM [HRM].[tbl_EmployeeAttendance] [Attendance], [HRM].[tbl_EmployeeInfo] [Info]
WHERE [Attendance].[Status] IN ('Early Left', 'Present', 'Half Day', 'Late In')
AND [Info].[ID] = [Attendance].[EmpCode] AND [Attendance].[EmpCode] = 266
AND CAST([Attendance].[AttendanceTimeIn] AS DATE) >= '2018-08-01'
AND CAST([Attendance].[AttendanceTimeOut] AS DATE) <= '2018-08-15'
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