Python builtins.OSError OSError：[Errno 22]无效的参数

Question

我是python的初学者，我在获取一条简单路线的数据时遇到上述错误，并且没有编写任何逻辑，我只是​​将用户重定向到新模板。

我已经在github上添加了这个项目，并且因为这个而切换了分支是..？

我能够正确打开主页，但仪表板显示了此问题

    from flask import Flask, render_template, request, flash, redirect, url_for, session, logging
    from firebase import firebase
    from wtforms import Form, StringField, TextAreaField, PasswordField, validators
    from passlib.hash import sha256_crypt
    import json
    from functools import wraps

    app = Flask(__name__)
    firebase = firebase.FirebaseApplication('https://androidone-43cbb.firebaseio.com/', None)


    @app.route('/')
    def index():
    return render_template('home.html')


    @app.route('/testing')
    def testing():
        return '<h1>This is another testing page</h1>'


    # Dashboard
    @app.route('/dashboard')
    ##@is_logged_in 
    def dashboard():
        return render_template('displayallusers.html')


    if __name__ == '__main__':
        app.run(debug=True)

错误错误信息如下

builtins.OSError
OSError: [Errno 22] Invalid argument
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 2309, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 2295, in wsgi_app
response = self.handle_exception(e)
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 1741, in handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\_compat.py", line 35, in reraise
raise value
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 2292, in wsgi_app
response = self.full_dispatch_request()
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 1815, in full_dispatch_request
rv = self.handle_user_exception(e)
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 1718, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\_compat.py", line 35, in reraise
raise value
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 1813, in full_dispatch_request
rv = self.dispatch_request()
File "C:\Users\Rakeshvasal\AppData\Local\Programs\Python\Python36-32\lib\site-packages\flask\app.py", line 1799, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "D:\Rakesh\DemoTest\FlaskTest\firebaseinit.py", line 37, in dashboard
from _pydevd_bundle.pydevd_custom_frames import CustomFramesContainer, custom_frames_container_init

Answer 1

我遇到了同样的问题，给定帖子上的所有操作都显示了相同的错误，最后得到了以下代码来更改端口号：

from flask import Flask

app = Flask(__name__)


@app.route("/")
def hello():
    return "Hello World!"


if __name__ == "__main__":
    import os

    HOST = os.environ.get('SERVER_HOST', 'localhost')
    try:
        PORT = int(os.environ.get('SERVER_PORT', '5555'))
    except ValueError:
        PORT = 5555
    app.run(HOST, PORT)

我的端口号以前默认设置为5000，现在我将其更改为5555，您可以将其更改为任何端口号

Answer 2

我也遇到了这个问题，参考楼上的方法，将端口号修改为5555，问题就解决了。 这个问题困扰了我一天

from  flask import Flask,jsonify
app = Flask(__name__)
@app.route('/index')
data={
    'name':'python',
    'age':'18'
}
return jsonify(data)


if __name__=="__main__":
     app.run(port=5555,debug=True)

访问链接：127.0.0.1：5555 /索引