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如何编写具有多个联接的Spring Data JPA规范?

[英]How to write a Spring Data JPA Specification with multiple joins?

我正在处理的项目是使用支持实体过滤的JHipster生成的,该过滤器在后台使用了Spring Data JPA规范。

该模型如下(在JDL中):

entity Student {
    name String
}

entity Course {
    name String
}

entity Enrollment {
}

entity Attendance {
    date LocalDate
}

relationship OneToMany {
    Student to Enrollment(student required),
    Course to Enrollment(course required),
    Enrollment to Attendance(enrollment required)
}

filter all
service all with serviceClass

JHipster生成用于通过enrollmentId过滤Attendance的样板,但我想对其进行扩展以能够通过studentIdcourseId进行过滤。

因此,如何实现将执行类似查询的规范:

SELECT
  attendance.date, student.name as student, course.name as course
FROM attendance
JOIN enrollment
  ON enrollment.id = attendance.enrollment_id
JOIN student
  ON student.id = enrollment.student_id
  AND studend.id = 1
JOIN course
  ON course.id = enrollment.course_id
  AND course.id = 2;

遵循@GaëlMarziou的建议,我已经实现了一些简单的方法来创建Specification<Attendance>以便与StudentCourse 联接

我将字段,获取器和设置器添加到AttendanceCriteria类,并重新编译以更新JPA元模型:

private LongFilter studentId;

private LongFilter courseId;

public LongFilter getStudentId() {
    return studentId;
}

public void setStudentId(LongFilter studentId) {
    this.studentId = studentId;
}

public LongFilter getCourseId() {
    return courseId;
}

public void setCourseId(LongFilter courseId) {
    this.courseId = courseId;
}

这是AttencanceQueryService类的更新的片段:

private Specification<Attendance> createSpecification(AttendanceCriteria criteria) {
    Specification<Attendance> specification = Specification.where(null);
    if (criteria != null) {
        if (criteria.getId() != null) {
            specification = specification.and(buildSpecification(criteria.getId(), Attendance_.id));
        }
        if (criteria.getDate() != null) {
            specification = specification.and(buildRangeSpecification(criteria.getDate(), Attendance_.date));
        }
        if (criteria.getEnrollmentId() != null) {
            specification = specification.and(buildReferringEntitySpecification(criteria.getEnrollmentId(), Attendance_.enrollment, Enrollment_.id));
        }
        if (criteria.getStudentId() != null) {
            specification = specification.and(buildJoinSpecification(criteria.getStudentId(), Attendance_.enrollment, Enrollment_.student, Student_.id));
        }
        if (criteria.getCourseId() != null) {
            specification = specification.and(buildJoinSpecification(criteria.getCourseId(), Attendance_.enrollment, Enrollment_.course, Course_.id));
        }
    }
    return specification;
}

private <REFERENCE, JOIN, FILTER extends Comparable<? super FILTER>> Specification<Attendance> buildJoinSpecification(RangeFilter<FILTER> filter, SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> valueField) {
    Specification<Attendance> result = Specification.where((Specification) null);
    if (filter.getEquals() != null) {
        result = this.equalsSpecification(reference, joinField, valueField, filter.getEquals());
    }
    if (filter.getIn() != null) {
        result = this.valueIn((SingularAttribute) reference, joinField, valueField, filter.getIn());
    }
    return result;
}

private <REFERENCE, JOIN, FILTER> Specification<Attendance> equalsSpecification(SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> idField, FILTER value) {
    return (root, query, builder) ->
        builder.equal(root.join(reference).join(joinField).get(idField), value);
}

private <REFERENCE, JOIN, FILTER> Specification<Attendance> valueIn(SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> valueField, Collection<FILTER> values) {
    return (root, query, builder) -> {
        CriteriaBuilder.In<FILTER> in = builder.in(root.join(reference).join(joinField).get(valueField));
        for (FILTER value : values) {
            in = in.value(value);
        }
        return in;
    };
}

我希望这对某人有帮助,功劳归于@GaëlMarziouBlackdread / Yoann Caplain

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