创建 Spring 数据 Jpa 规范方法没有JOINS

Question

我有一个Spring-MVC在线商店项目，我使用Spring Boot和Hibernate 。 我决定使用Specification进行过滤。 因此，我使用JOINS为规范编写了一个方法。 请告诉我如何在没有JOIN的情况下编写相同的方法。

茶叶规格 class：

public static Specification<Tea> getTeasByFilter(Long colorId, Long typeId, Long countryId) {
        return (root, query, criteriaBuilder) -> {
            Join<Object, Object> colorJoin = root.join(Tea_.TEA_COLOR);
            Join<Object, Object> typeJoin = root.join(Tea_.TEA_TYPE);
            Join<Object, Object> countryJoin = root.join(Tea_.COUNTRIES);
            Predicate countryPredicate = criteriaBuilder.equal(countryJoin.get(Countries_.ID), countryId);
            Predicate colorPredicate = criteriaBuilder.equal(colorJoin.get(TeaColor_.ID), colorId);
            Predicate typePredicate = criteriaBuilder.equal(typeJoin.get(TeaColor_.ID), typeId);
            return criteriaBuilder.and(colorPredicate, typePredicate, countryPredicate);
        };
    }

饮料类（茶扩展饮料）：

@Inheritance(strategy = InheritanceType.JOINED)
public class Drink {

    // Fields
    //
    private @Id
    @GeneratedValue
    Long id;

    private String name;

    private BigDecimal price;

    private String about;

    @Column(name = "is_deleted")
    private boolean isDeleted;

    // Relationships
    //
    @ManyToOne
    @JoinColumn(name = "packaging_id")
    private Packaging packaging;

    @ManyToOne
    @JoinColumn(name = "manufacturer_id")
    private Manufacturer manufacturer;

    @ManyToOne
    @JoinColumn(name = "country_id")
    private Countries countries;
}

public class Tea extends Drink {

    // Relationships
    //
    @ManyToOne
    @JoinColumn(name = "type_id")
    private TeaType teaType;

    @ManyToOne
    @JoinColumn(name = "color_id")
    private TeaColor teaColor;
}

Answer 1

public class TeaSpecification {

    public static Specification<Tea> getTeasByFilter(Long colorId, Long typeId, Long countryId) {
        return (root, query, criteriaBuilder) -> {
            Predicate colorPredicate = criteriaBuilder
                    .equal(root.get(Tea_.teaColor).get(TeaColor_.id), colorId);
            Predicate typePredicate = criteriaBuilder
                    .equal(root.get(Tea_.teaType).get(TeaType_.id), typeId);
            Predicate countryPredicate = criteriaBuilder
                    .equal(root.get(Tea_.countries).get(Countries_.id), countryId);
            return criteriaBuilder.and(colorPredicate, typePredicate, countryPredicate);
        };
    }
}