[英]How do I change the background color onclick on python using turtle?
我一直在尝试使用乌龟在背景中的每次单击时触发这些颜色。 如果有人可以帮助我提前感谢您的答复,那将是非常不错的!
import turtle
import random
f = turtle.pen()
BG=turtle.Screen()
colors = ['blue', 'red', 'yellow', 'green']
BG.bgcolor("black")
richard.pencolor("orange")
richard.penup()
def draw(x,y):
richard.goto(x,y)
richard.pendown()
for x in range(360):
richard.forward(200)
richard.left(108)
richard.forward(205)
richard.left(108)
richard.forward(210)
richard.left(108)
richard.forward(215)
richard.left(1)
richard.forward(220)
richard.left(108)
richard.forward(225)
richard.left(108)
richard.tilt(20)
richard.speed(90)
richard.pencolor()
richard.pencolor(random.choice(colors))
richard.bgcolor()
richard.bgcolor(random.choice(colors))
if(x % 2 ==1):
richard.bgcolor(random.choice(colors))
if(x % 2 ==1):
richard.pencolor(random.choice(colors))
richard.penup()
BG.onclick(draw())
您的主要问题是以下行:
BG.onclick(draw())
我们需要将draw
函数本身传递给onclick()
,而不是draw()
返回的None
:
BG.onclick(draw)
一个简单的示例,仅在单击窗口时更改背景颜色:
from turtle import Screen, Turtle
from random import choice
COLORS = ['blue', 'red', 'yellow', 'green']
screen = Screen()
screen.bgcolor("black")
def draw(x, y):
color = choice(COLORS)
while color == screen.bgcolor(): # don't use same color twice in a row
color = choice(COLORS)
screen.bgcolor(color)
screen.onclick(draw)
screen.mainloop()
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