如何使用pybind11从virtualenv运行python解释器？

Question

我正在尝试使用pybind11库从称为env_tensorflow的python环境中执行python解释器。

即使我包含了cpp文件并将其链接到该环境（ env_tensorflow ）中包含的pybind11库，解释器也会将其二进制路径打印为：

在/ usr / bin中/ python3

但是，我希望输出为：

/ home / user中/ miniconda3 / ENVS / env_tensorflow /斌/ python3

我究竟做错了什么？ 如何从特定环境运行python解释器？

main.cpp中

#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/Python.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/pybind11.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/embed.h"

namespace py = pybind11;
int main() {
    py::scoped_interpreter guard{};
    py::module sys = py::module::import("sys");
    py::print(sys.attr("executable"));
    //prints: /usr/bin/python3
    //expected print: /home/user/miniconda3/envs/env_tensorflow/bin/python3
    return 0;
}

的CMakeLists.txt

cmake_minimum_required(VERSION 3.12)
project(my_proj)
set(CMAKE_CXX_STANDARD 11)

add_library(my_python3.6m SHARED IMPORTED)
set_target_properties(my_python3.6m PROPERTIES
        IMPORTED_LOCATION "/home/user/miniconda3/envs/env_tensorflow/lib/libpython3.6m.so"
        INTERFACE_INCLUDE_DIRECTORIES "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/"
        )

add_executable(my_proj main.cpp)
target_link_libraries(my_proj my_python3.6m)

Answer 1

您需要激活Conda环境：

source activate env_tensorflow

完成此操作后，您应该能够使用正确的Python解释器运行cmake，make和您的应用程序。 您可能不需要CMake中的python3.6m目标，只要在构建过程中环境处于活动状态，就可以python3.6m链接到python3.6m 。