Python：捕获 logging.exception() 调用

Question

我试图捕捉一个没有引发的异常，只是记录了。 有没有办法做到这一点？

def exampleFunction():
    try:
        x = 1 / 0
    except Exception:
        logging.exception('divide by 0 error here.')

try:
    exampleFunction()
except <condition based on if logging.exception was called>
    print('there was a divide by 0 error when I called exampleFunction()')

Answer 1

我假设 exampleFunction 位于您不拥有的一些可怕的第三方代码中，否则有很多更好的选择。

你可以做什么：

import logging # make sure this is the FIRST import of logging
import horrible_third_party_lib

def catch_log(msg):
   # do something when this is called
old_logging = logging.exception
try:
    logging.exception=catch_log
    horrible_third_party_lib.exampleFunction()
finally:
    logging.exception=old_logging

然后，您可以在函数中执行任何您想做的事情。 它对导入顺序既可怕又敏感，但我已经使用了它并且它有效（scikit learn 做了类似令人反感的事情......）

Answer 2

问题：我正在尝试捕获异常
问题标题应改写为“我正在尝试重新提出例外”

阅读Python 文档#raise
似乎有点双重工作，但你可以这样做：

def exampleFunction():
    try:
        x = 1 / 0
    except Exception as e:
        print("logging.exception({})".format(e))
        raise

try:
    exampleFunction()
except ZeroDivisionError as e:
    print('there was a divide by 0 error when I called exampleFunction()')

输出：

 logging.exception(division by zero) there was a divide by 0 error when I called exampleFunction()

用 Python 测试：3.5.3