Python连接四，不能使用库

Question

我想在 python 3.7 中连接四个，但我们很快就卡住了，我们真的很新，所以这就是原因。 我们基本上希望将玩家 1 和 2 的 1 和 2 放在下面的网格中，但是当我们在同一列中输入玩家 1 和 2 时，它不起作用。 我很想有人帮助我们，因为我们已经坚持了很长时间，在此先感谢！ 附： 我们不想使用任何插件或添加到 python 中，只是常规的 if、def、while 等语句。

ROW_COUNT = 6
COLUMN_COUNT = 7

row6 = [0, 0, 0, 0, 0, 0, 0]
row5 = [0, 0, 0, 0, 0, 0, 0]
row4 = [0, 0, 0, 0, 0, 0, 0]
row3 = [0, 0, 0, 0, 0, 0, 0]
row2 = [0, 0, 0, 0, 0, 0, 0]
row1 = [0, 0, 0, 0, 0, 0, 0]
Board=[row6, row5, row4, row3, row2, row1]

def drop_piece(Board, row, Column, piece):
    Board[row][Column] = piece

def is_valid_location(Board, Column):
    return Board[0][Column] ==0

def get_next_open_row(Board, Column):
    for r in range(ROW_COUNT):
        if Board[r][Column]==0:
            return r

gameOver = False
turn = 0
while not gameOver:
    if turn == 0:
        Column = int(input("Player 1, Make your turn(0-6):"))
        if is_valid_location(Board ,Column):
            row = get_next_open_row(Board, Column)
            drop_piece(Board, row, Column, 1)
            turn = turn + 1
    else:
        Column = int(input("Player 2, Make your turn(0-6):"))
        if is_valid_location(Board, Column):
            row = get_next_open_row(Board, Column)
            drop_piece(Board, row, Column, 2)
        turn = turn - 1

    print(row1)
    print(row2)
    print(row3)
    print(row4)
    print(row5)
    print(row6)

Answer 1

这应该会让你重新开始，仍然需要编写gameOver部分。

一个问题是您将显示定义为：

row6 = [0, 0, 0, 0, 0, 0, 0]
row5 = [0, 0, 0, 0, 0, 0, 0]
row4 = [0, 0, 0, 0, 0, 0, 0]
row3 = [0, 0, 0, 0, 0, 0, 0]
row2 = [0, 0, 0, 0, 0, 0, 0]
row1 = [0, 0, 0, 0, 0, 0, 0]
Board=[row6, row5, row4, row3, row2, row1]

但是，打印输出

print(row1) #Prints First
print(row2)
print(row3)
print(row4)
print(row5)
print(row6) #Prints Last

使其在屏幕上显示为：

row1 = [0, 0, 0, 0, 0, 0, 0]
row2 = [0, 0, 0, 0, 0, 0, 0]
row3 = [0, 0, 0, 0, 0, 0, 0]
row4 = [0, 0, 0, 0, 0, 0, 0]
row5 = [0, 0, 0, 0, 0, 0, 0]
row6 = [0, 0, 0, 0, 0, 0, 0]

另一个是你的切换很容易坏：

if turn == 0:
    if is_valid_location(Board ,Column):
        turn = turn + 1
else:
    turn = turn - 1

这意味着 turn 可以增加的唯一方法是如果turn为 0 并且Column是有效位置，否则它将继续是玩家 2 的回合并继续递减。

这是我的代码，现在显示是基于计数变量中设置的行和列动态进行的，切换是基于布尔值的，并且只切换播放器，为用户选择添加验证，并且打印是在一个环形：

ROW_COUNT = 6
COLUMN_COUNT = 7

Board = [] # Define the Board list
# Appends a list of 0s COLUMN_COUNT long, to the Board list, ROW_COUNT amount of times.
for x in range(ROW_COUNT): Board.append(list([0] * COLUMN_COUNT))

def drop_piece(Board, row, Column, piece):
    Board[row][Column] = piece

def is_valid_location(Board, Column):
    # Checks that the top row for the selected column is 0
    return Board[-1][Column] == 0

def get_next_open_row(Board, Column):
    for r in range(ROW_COUNT):
        if Board[r][Column]==0:
            return r

gameOver = False

turn = True

while not gameOver:
    # Boolean toggle True = player 1, False = player 2
    if turn: player = 1
    else: player = 2
    Column = int(input("Player " + str(player) +", Make your turn(0-6):"))
    if is_valid_location(Board, Column):
        row = get_next_open_row(Board, Column)
        drop_piece(Board, row, Column, player)
        turn = not turn
    else: print("Invalid selection")

    # prints the reversed Board, since printing needs to be last printed first
    for row in reversed(Board):
        print(row)