[英]Count the number of times a letter appears in a word and put them in the following format:
我必须创建一个程序,该程序给定一个短语来计算字母在每个单词中出现的次数并以这种方式打印:
输入:
i see it
输出:
[('i', 1), ('s', 1), ('e', 2), ('i', 1), ('t', 1)]
我的代码仅适用于第一个单词。您能帮我吗?
inicialString=str(input())
words=inicialString.split(" ")
def countTheLetters(t):
for word in words:
thingsList=[]
for x in word:
n=word.count(x)
j=x,n
thingsList.append(j)
return thingsList
print(countTheLetters(words))
我的输出:
[('i', 1)]
我试图替换返回的ThingsList,但是它仅适用于最后一个单词。
您每次thingsList
for word in words:
时都使用for word in words:
循环,所以您只会得到最后一个单词。
在第一个for
语句之前放置thingsList = []
。
问题是您在检查第一个单词后立即从函数中返回,而是应将当前单词的结果附加到某个最终列表中,并在处理完所有单词后返回它。
inicialString='i see it'
words=inicialString.split(" ")
def countTheLetters(t):
ret = []
for word in words:
thingsList=[]
for x in word:
n=word.count(x)
j=x,n
if not j in thingsList:
thingsList.append(j)
ret.extend(thingsList)
return ret
print(countTheLetters(words))
输出:
[('i', 1), ('s', 1), ('e', 2), ('i', 1), ('t', 1)]
问题是您要在“ for word in word”循环中的每个迭代中重置“ thingsList”,并且还仅在进行一次迭代后返回thingsList列表。
inicialString=str(input())
words=inicialString.split(" ")
def countTheLetters(t):
thingsList=[]
for word in words:
for x in word:
n=word.count(x)
j=x,n
thingsList.append(j)
return thingsList
print(countTheLetters(words))
更新了代码,请立即检查
inicialString=str(input())
words=inicialString.split(" ")
def countTheLetters(t):
thingsList=[]
for word in words:
for x in word:
n=word.count(x)
j=x,n
thingsList.append(j)
return thingsList
print(countTheLetters(words))
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