如何使用函数将新键和值附加到列表字典中

Question

{'Brazil': [19000000, 810000.00], 'Japan': [128000000, 350000.0]}

如果我有dict1保存有关国家名称、人口和地区的数据，并且我想使用一个函数以与当前字典相同的格式添加新的国家、人口和地区（其中值包含在列表中） ，我该怎么做？

Answer 1

使用以下代码：

dict1 = {'Brazil': [19000000, 810000.00], 'Japan': [128000000, 350000.0]} #initial dict

def addToDict(c, p, a):
    #add new values to dict1, here we are adding country(c) as key, [population(p), area(a)] as value.
    dict1[c] = [p, a] #dict[c] = [p,a] <-- [p,a] are values assigned to the key identified-in/new-key in dict1
    return dict1      #optional - I used it just to see the final value.

print (addToDict('India', 1000000000, 10098978.778)) #main call

#result --> {'Brazil': [19000000, 810000.0], 'Japan': [128000000, 350000.0], 'India': [1000000000, 10098978.778]}

Answer 2

查看addNew函数：

dict1 = {'Brazil': [19000000, 810000.00], 'Japan': [128000000, 350000.0]}

def addNew(dict, country, population, area):
    dict.update({country: [population, area]})

addNew(dict1, 'countryTest', 200000, 1000.00)

print(dict1)

输出：

{'Brazil': [19000000, 810000.0], 'Japan': [128000000, 350000.0], 'countryTest': [200000, 1000.0]}

Answer 3

pop = 10
area = 20
name = "A"
dict1[name] = [pop, area]

Answer 4

dict1 = {}

def appendDict(country, population, area):
    dict1[country] = [population, area]

appendDict("Brazil", "19000000", "810000.00")
appendDict("Japan", "128000000", "350000.0")

print(dict1)

Answer 5

这是一个很好的例子：

travel_log = [
{
  "country": "France",
  "visits": 12,
  "cities": ["Paris", "Lille", "Dijon"]
},
{
  "country": "Germany",
  "visits": 5,
  "cities": ["Berlin", "Hamburg", "Stuttgart"]
},
]

dict1 = {}
def add_new_country(country,visits,cities):
  dict1 = {}
  dict1['country']= country
  dict1['visits'] = visits
  dict1['cities'] = cities
  travel_log.append(dict1)

add_new_country("Russia", 2, ["Moscow", "Saint Petersburg"])
print(travel_log)