使用SQL Server生成15分钟插槽的数据平均值
[英]Generating data averages for 15min slots using SQL Server
问题描述
我有一个SQL Server表，如下所示。
CREATE TABLE [dbo].[ChannelData](
[Id] [int] IDENTITY(1,1) NOT NULL,
[ChannelId] [int] NOT NULL,
[ChannelValue] [decimal](10, 2) NULL,
[ChannelDataLogTime] [datetime] NOT NULL,
[Active] [bit] NULL,CONSTRAINT [PK_ChannelData] PRIMARY KEY CLUSTERED ( [Id] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]) ON [PRIMARY]
示例数据如下：::
+----+-----------+--------------+-------------------------+--------+
| Id | ChannelId | ChannelValue | ChannelDataLogTime | Active |
+----+-----------+--------------+-------------------------+--------+
| 1 | 9 | 5.46 | 2015-06-09 14:00:11.463 | 1 |
| 2 | 9 | 8.46 | 2015-06-09 14:01:11.503 | 1 |
| 3 | 9 | 3.46 | 2015-06-09 14:02:27.747 | 1 |
| 4 | 9 | 6.46 | 2015-06-09 14:03:11.503 | 1 |
| 5 | 9 | 1.46 | 2015-06-09 14:04:11.530 | 1 |
| 6 | 9 | 4.46 | 2015-06-09 14:05:11.537 | 1 |
| 7 | 9 | 7.46 | 2015-06-09 14:06:11.547 | 1 |
| 8 | 9 | 2.46 | 2015-06-09 14:07:33.983 | 1 |
| 9 | 9 | 5.46 | 2015-06-09 14:08:11.570 | 1 |
| 10 | 9 | 8.46 | 2015-06-09 14:09:11.603 | 1 |
| 11 | 9 | 3.46 | 2015-06-09 14:10:11.613 | 1 |
| 12 | 9 | 6.47 | 2015-06-09 14:11:11.623 | 1 |
| 13 | 9 | 1.47 | 2015-06-09 14:12:24.497 | 1 |
| 14 | 9 | 4.47 | 2015-06-09 14:13:11.623 | 1 |
| 15 | 9 | 7.47 | 2015-06-09 14:14:11.650 | 1 |
| 16 | 9 | 2.47 | 2015-06-09 14:15:11.707 | 1 |
| 17 | 9 | 5.47 | 2015-06-09 14:16:11.707 | 1 |
| 18 | 9 | 8.47 | 2015-06-09 14:17:25.647 | 1 |
| 19 | 9 | 3.47 | 2015-06-09 14:18:11.707 | 1 |
| 20 | 9 | 6.47 | 2015-06-09 14:19:11.753 | 1 |
| 21 | 9 | 1.47 | 2015-06-09 14:20:11.760 | 1 |
| 22 | 9 | 4.47 | 2015-06-09 14:21:11.790 | 1 |
| 23 | 9 | 7.47 | 2015-06-09 14:22:29.500 | 1 |
| 24 | 9 | 2.47 | 2015-06-09 14:23:11.907 | 1 |
| 25 | 9 | 5.47 | 2015-06-09 14:24:12.057 | 1 |
| 26 | 9 | 8.47 | 2015-06-09 14:25:11.817 | 1 |
| 27 | 9 | 3.47 | 2015-06-09 14:26:11.837 | 1 |
| 28 | 9 | 6.47 | 2015-06-09 14:27:32.253 | 1 |
| 29 | 9 | 1.47 | 2015-06-09 14:28:11.870 | 1 |
| 30 | 9 | 4.47 | 2015-06-09 14:29:11.870 | 1 |
| 31 | 9 | 7.50 | 2015-06-09 16:00:13.313 | 1 |
| 32 | 9 | 2.50 | 2015-06-09 16:01:13.260 | 1 |
| 33 | 9 | 5.50 | 2015-06-09 16:02:13.290 | 1 |
| 34 | 9 | 8.50 | 2015-06-09 16:03:13.270 | 1 |
| 35 | 9 | 3.50 | 2015-06-09 16:04:32.827 | 1 |
| 36 | 9 | 6.50 | 2015-06-09 16:05:13.323 | 1 |
| 37 | 9 | 1.50 | 2015-06-09 16:06:13.330 | 1 |
| 38 | 9 | 4.50 | 2015-06-09 16:07:13.337 | 1 |
| 39 | 9 | 7.50 | 2015-06-09 16:08:13.313 | 1 |
| 40 | 9 | 2.50 | 2015-06-09 16:09:28.497 | 1 |
| 41 | 9 | 5.50 | 2015-06-09 16:10:13.370 | 1 |
| 42 | 9 | 8.50 | 2015-06-09 16:11:13.417 | 1 |
| 43 | 9 | 3.50 | 2015-06-09 16:12:13.540 | 1 |
| 44 | 9 | 6.50 | 2015-06-09 16:13:13.577 | 1 |
| 45 | 9 | 1.50 | 2015-06-09 16:14:33.880 | 1 |
| 46 | 9 | 4.50 | 2015-06-09 16:15:13.453 | 1 |
| 47 | 9 | 7.50 | 2015-06-09 16:16:13.500 | 1 |
| 48 | 9 | 2.50 | 2015-06-09 16:17:13.497 | 1 |
| 49 | 9 | 5.50 | 2015-06-09 16:18:13.503 | 1 |
| 50 | 9 | 8.50 | 2015-06-09 16:19:38.717 | 1 |
| 51 | 9 | 3.50 | 2015-06-09 16:21:13.567 | 1 |
| 52 | 9 | 6.50 | 2015-06-09 16:22:13.557 | 1 |
| 53 | 9 | 1.50 | 2015-06-09 16:23:14.163 | 1 |
| 54 | 9 | 4.50 | 2015-06-09 16:24:13.607 | 1 |
| 55 | 9 | 7.50 | 2015-06-09 16:25:38.783 | 1 |
| 56 | 9 | 2.50 | 2015-06-09 16:27:13.660 | 1 |
| 57 | 9 | 5.51 | 2015-06-09 16:28:13.710 | 1 |
| 58 | 9 | 8.51 | 2015-06-09 16:29:13.703 | 1 |
| 59 | 9 | 3.51 | 2015-06-09 16:30:13.713 | 1 |
+----+-----------+--------------+-------------------------+--------+
现在，我将在一段时间内生成15分钟的平均数据，包括开始日期和结束日期。 可以很好地解决任何问题。
我遇到的情况是数据会丢失一段时间。 由于缺少15分钟时隙的数据，因此又错过了15分钟时隙。 我需要的是列出15分钟的时间段，即使使用SQL查询在该时间段内数据不可用。
SELECT
Avg(chnldata.ChannelValue) AS ChannelValue,
DATEADD(minute,FLOOR(DATEDIFF(minute,0,ChannelDataLogTime)/15)*15,0) as HourlyDateTime,
chnldata.ChannelId as Id
FROM ChannelData as chnldata
WHERE chnldata.ChannelId in (9) AND chnldata.ChannelDataLogTime >= '06/09/2015' AND chnldata.ChannelDataLogTime < '06/11/2015 23:59:50'
GROUP BY chnldata.ChannelId, DATEADD(minute,FLOOR(DATEDIFF(minute,0,ChannelDataLogTime)/15)*15,0)
这是现有的15分钟平均查询。 但是它不会显示缺少15分钟的广告位。 当前输出为：
+--------------+-------------------------+----+
| ChannelValue | HourlyDateTime | Id |
+--------------+-------------------------+----+
| 5.129333 | 2015-06-09 14:00:00.000 | 9 |
| 4.803333 | 2015-06-09 14:15:00.000 | 9 |
| 5.033333 | 2015-06-09 16:00:00.000 | 9 |
| 5.270769 | 2015-06-09 16:15:00.000 | 9 |
| 3.510000 | 2015-06-09 16:30:00.000 | 9 |
+--------------+-------------------------+----+
所需的输出是：::
+--------------+-------------------------+----+
| ChannelValue | HourlyDateTime | Id |
+--------------+-------------------------+----+
| 5.129333 | 2015-06-09 14:00:00.000 | 9 |
| 4.803333 | 2015-06-09 14:15:00.000 | 9 |
| NULL | 2015-06-09 14:30:00.000 | 9 |
| NULL | 2015-06-09 14:45:00.000 | 9 |
| NULL | 2015-06-09 15:00:00.000 | 9 |
| NULL | 2015-06-09 15:15:00.000 | 9 |
| NULL | 2015-06-09 15:30:00.000 | 9 |
| NULL | 2015-06-09 15:45:00.000 | 9 |
| 5.033333 | 2015-06-09 16:00:00.000 | 9 |
| 5.270769 | 2015-06-09 16:15:00.000 | 9 |
| 3.510000 | 2015-06-09 16:30:00.000 | 9 |
+--------------+-------------------------+----+
3 个解决方案
解决方案1
1 2018-12-03 18:08:42
正确加入CTE，该CTE在您的时间范围内具有所有可能的15分钟间隔。
解决方案2
0 2018-12-03 19:05:08
建立时间范围的CTE，可以通过多种方式完成，但是笛卡尔乘积法可能比许多方法要快，如果您想提高速度，最好建立一个静态日期表，也许还有一个日期和时间表
;WITH mins as (SELECT 0 as q union select 15 union select 30 union select 45),
dats as (SELECT MIN(ChannelDataLogTime) as t1, max(ChannelDataLogTime) as t2 from channeldata),
ranges as (SELECT CAST(t1 as date) s1 FROM dats
union all
SELECT dateadd(day,1,r.s1) from ranges r where r.s1< (select t2 from dats)
),
hrs as (select 0 h union all select h + 1 from hrs where h < 23), --hours 0 to 23
slots as (select dateadd(MINUTE,mins.q,dateadd(hour,hrs.h,cast(ranges.s1 as datetime2))) as strt from mins,ranges,hrs ),
ids as (SELECT distinct ChannelId from ChannelData),
allslot as (select channelid, strt from slots,ids)
SELECT count(0) as x,
coalesce(Avg(chnldata.ChannelValue) , 0) AS ChannelValue,
s.strt HourlyDateTime,
s.ChannelId as Id
FROM ChannelData as chnldata
RIGHT JOIN allslot s on s.strt <= ChannelDataLogTime and ChannelDataLogTime < dateadd(minute,15,s.strt) and s.ChannelId = chnldata.ChannelId
WHERE chnldata.ChannelId is null or chnldata.ChannelId in (9) AND chnldata.ChannelDataLogTime >= '20150906' AND chnldata.ChannelDataLogTime < '20151123'
GROUP BY s.ChannelId, s.strt
解决方案3
0 2018-12-03 19:18:33
考虑maxrecursion选项的局限性。
DECLARE @StartDT DATETIME = '2015-06-09';
DECLARE @EndDT DATETIME = '2015-06-12'; -- moved to the next day to use >= and < operators correctly
;WITH
[Interval]
AS
(
SELECT
[Start] = @StartDT
,[End] = DATEADD(MINUTE, 15, @StartDT)
UNION ALL
SELECT
[Start] = [End]
,[End] = DATEADD(MINUTE, 15, [End])
FROM [Interval]
WHERE (1 = 1)
AND ([End] < @EndDT)
),
[Available]
AS
(
SELECT
[Start] = CONVERT(SMALLDATETIME, MIN([CD].[ChannelDataLogTime]))
,[End] = CONVERT(SMALLDATETIME, MAX([CD].[ChannelDataLogTime]))
FROM [dbo].[ChannelData] AS [CD]
WHERE (1 = 1)
AND (@StartDT <= [CD].[ChannelDataLogTime] AND [CD].[ChannelDataLogTime] < @EndDT)
)
SELECT
[ChannelValue] = AVG([CD].[ChannelValue])
,[HourlyDateTime] = [I].[Start]
,[Id] = [CD].[ChannelId]
FROM [Available] AS [A]
INNER JOIN [Interval] AS [I]
ON ([A].[Start] <= [I].[Start] AND [I].[Start] <= [A].[End])
LEFT OUTER JOIN [dbo].[ChannelData] AS [CD]
ON
(
([CD].[ChannelId] IN (9))
AND ([I].[Start] <= [CD].[ChannelDataLogTime] AND [CD].[ChannelDataLogTime] < [I].[End])
)
GROUP BY
[I].[Start]
,[CD].[ChannelId]
ORDER BY
[I].[Start]
OPTION (MAXRECURSION 32767);
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