Python-如何在文本中打印出一行

Question

所以我一直在尝试使用bs4并设法打印出文本。 现在，我设法打印出了更多的init var ajaxsearch 。

我编写了一个代码，在其中打印出所有包含javascript的代码，并在其中以var ajaxsearch开头的代码进行打印：

  try:
        product_li_tags = bs4.find_all('script', {'type': 'text/javascript'})
    except Exception:
        product_li_tags = []

    special_code = ''
    for s in product_li_tags:
        if s.text.strip().startswith('var ajaxsearch'):
            special_code = s.text
            break

    print(special_code)

我得到的输出是：

var ajaxsearch = false;
var combinationsFromController ={
  "224114": {
    "attributes_values": {
      "4": "5.5"
    },
    "attributes": [
      22
    ],

    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'22'"
  },
  "224140": {
    "attributes_values": {
      "4": "6"
    },
    "attributes": [
      23
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'23'"
  },
  "224160": {
    "attributes_values": {
      "4": "6.5"
    },
    "attributes": [
      24
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'24'"
  },
  "224139": {
    "attributes_values": {
      "4": "7"
    },
    "attributes": [
      25
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'25'"
  },
  "224138": {
    "attributes_values": {
      "4": "7.5"
    },
    "attributes": [
      26
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'26'"
  },
  "224113": {
    "attributes_values": {
      "4": "8"
    },
    "attributes": [
      27
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'27'"
  },
  "224129": {
    "attributes_values": {
      "4": "8.5"
    },
    "attributes": [
      28
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'28'"
  },
  "224161": {
    "attributes_values": {
      "4": "9"
    },
    "attributes": [
      29
    ],
    "unit_impact": 0,
    "minimal_quantity": "1",
    "date_formatted": "",
    "available_date": "",
    "id_image": -1,
    "list": "'29'"
  }
};
var contentOnly = false;
var Blank = 1;
var Format = 2;

意思是当我打印出s.text时。 我将得到上面代码的输出。 小型修改：如果我尝试执行if s.text.strip().startswith('var combinationsFromController'):它不会找到该值，并且如果if 'var combinationsFromController' in s.text.strip(): if s.text.strip().startswith('var combinationsFromController'): ，我也无法找到该值if 'var combinationsFromController' in s.text.strip():它将打印出与上述相同的输出。

但是我的问题是我只想能够打印出var combinationsFromController groupsFromController并跳过其余的部分，以后我可以使用json.loads将值转换为json，但是在此之前，我的问题是，如何打印以便可以管理只具有值var combinationsFromController的值？

编辑：可能解决了！

for s in product_li_tags:
            if 'var combinationsFromController' in s.text.strip():
                for line in s.text.splitlines():
                    if line.startswith('var combinationsFromController'):
                        get_full_text = line.strip()
                        get_config = get_full_text.split(" = ")
                        cut_text = get_config[1][:-1]
                        get_json_values = json.loads(cut_text)

Answer 1

如果我正确理解您的问题，您有121行的字符串代表5个JavaScript变量，并且您想获得仅包含第二个变量的子字符串。

您可以使用Python字符串操作，如下所示：

start = special_code.split('\n').index('var combinationsFromController ={')
end   = special_code.split('\n')[start + 1:].index('var contentOnly = false;')
print('\n'.join(lines[start:end + 3]))

使用方法str.index查找所需的javascript变量。 如果顺序变量是任意的 ，即您不知道目标变量之后的下一个变量的名称，您仍然可以使用类似的字符串操作来获取所需的子字符串。

lines = special_code.split('\n')
start = lines.index('var combinationsFromController ={')
end   = lines[-1]
for i, line in enumerate(lines[start + 1:]):
    if 'var' in line:
        end = start + i
        break
print('\n'.join(lines[start:end + 1]))

Answer 2

在表达式中使用re (\\{.*?\\}); 捕获之间的数据var combinationsFromController =和;var contentOnly = false;

import re

....
print(special_code)
jsonStr = re.search(r'(\{.*?\});', special_code, re.S).group(1)
combinationsFromController = json.loads(jsonStr)

for key in combinationsFromController:
    print(key)
    # 224114
    # 224140
    # 224160