[英]flask application: trying to jsonify a dictionary
背景信息
我正在尝试编写我的第一个 Flask/python REST API。 到目前为止,我有一个 GET 连接到 redis 数据库并尝试将字典转换为 json ......然后返回这些结果。
问题
当我尝试在我的 dict 对象上调用 jsonify 时,它失败并出现以下错误:
Traceback (most recent call last):
File "/usr/lib/python3.6/site-packages/flask/app.py", line 1982, in wsgi_app
response = self.full_dispatch_request()
File "/usr/lib/python3.6/site-packages/flask/app.py", line 1614, in full_dispatch_request
rv = self.handle_user_exception(e)
File "/usr/lib/python3.6/site-packages/flask/app.py", line 1517, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "/usr/lib/python3.6/site-packages/flask/_compat.py", line 33, in reraise
raise value
File "/usr/lib/python3.6/site-packages/flask/app.py", line 1612, in full_dispatch_request
rv = self.dispatch_request()
File "/usr/lib/python3.6/site-packages/flask/app.py", line 1598, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "/var/www/localhost/htdocs/widgets/widgets.py", line 51, in get_profile
return jsonify(res_dict)
File "/usr/lib/python3.6/site-packages/flask/json.py", line 263, in jsonify
(dumps(data, indent=indent, separators=separators), '\n'),
File "/usr/lib/python3.6/site-packages/flask/json.py", line 123, in dumps
rv = _json.dumps(obj, **kwargs)
File "/usr/lib/python3.6/json/__init__.py", line 238, in dumps
**kw).encode(obj)
File "/usr/lib/python3.6/json/encoder.py", line 201, in encode
chunks = list(chunks)
File "/usr/lib/python3.6/json/encoder.py", line 430, in _iterencode
yield from _iterencode_dict(o, _current_indent_level)
File "/usr/lib/python3.6/json/encoder.py", line 376, in _iterencode_dict
raise TypeError("key " + repr(key) + " is not a string")
TypeError: key b'email1' is not a string
代码如下所示:
20 def get_db_profile(mailbox):
21 """ connects to redis and queries for profile """
22 try:
23 my_redis = redis.Redis(connection_pool=POOL)
24 response = my_redis.hgetall(55555)
25 logging.info(response.keys())
26 logging.info(response.items())
27 #response = '123455555'
28 return response
29 except Exception as ex:
30 return "Error:", ex
47 @application.route("/widgets/api/<int:mailbox>", methods=['GET'])
48 def get_profile(mailbox):
49 res_dict = get_db_profile(mailbox)
50 # return application.response_class(jsonify(res_dict), content_type='application/json')
51 return jsonify(res_dict)
52 # return '12345'
53
我添加了一些日志,如您在第 25 行看到的那样,以查看 keys() 的样子。 这是我在日志文件中看到的:
lab-1:/var/www/localhost/htdocs/widgets# cat /tmp/widgets.log
root - INFO - dict_keys([b'email1', b'email2'])
Redis数据
这就是我创建 redis 数据的方式:
127.0.0.1:6379[5]> hmset 55555 email1 johndoe@hotmail.com email2 jd@yahoo.com
OK
127.0.0.1:6379[5]>
问题
我应该能够从 dict 对象转换为 json 字符串吗? 日志文件中的“b”是什么?
lab-1:/var/www/localhost/htdocs/widgets# cat /tmp/widgets.log
root - INFO - dict_keys([b'email1', b'email2'])
root - INFO - dict_items([(b'email1', b'johndoe@hotmail.com'), (b'email2', b'jd@yahoo.com')])
如何发回正确的 JSON 响应?
编辑 1
我找到了这个问题/答案: How to parse python b' string contains dict并基于此我试图将我的逻辑更改为如下所示:
47 @application.route("/pvmailprofiles/api/<int:mailbox>", methods=['GET'])
48 def get_profile(mailbox):
49 res_dict = get_db_profile(mailbox)
50 # return application.response_class(jsonify(res_dict), content_type='application/json')
51 #return jsonify(res_dict)
52 return res_dict[b'email1']
53 # return '12345'
54
第 52 行 - 您可以看到作为测试,我已经硬编码了 'b',然后是键名。 它有效 - 它返回特定的电子邮件地址。 但我需要找到一种方法来“只是”将所有内容转换为 json 并返回给被调用者。
你有没有试过像这样先导入json
import json
然后做
json.dumps(myDict)
然后在需要时再次加载它。
json.loads(response.text)
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