检查python列表中的序列

Question

我有一个清单[T20，T5，T10，T1，T2，T8，T16，T17，T9，T4，T12，T13，T18]

我已经删除了T，转换为整数类型并对列表进行排序以获得：

sorted_ids = [1,2,4,5,8,9,10,12,13,16,17,18,20]

我循环遍历列表并检查当前数字的下一个数字是否按数字顺序排列。 如果不是，我想在其位置插入“V” 。

因此最终列表应如下所示： [1,2，V，4,5，V，V，8,9,10，V，12,13，V，V，16,17,18，V，20]

但是，我无法在正确的位置插入精确的V值 。

def arrange_tickets(tickets_list):

    ids=[]
    for item in tickets_list:
        new_str=item.strip("T")
        ids.append(int(new_str))
    sorted_ids = sorted(ids)
    temp_ids = []
    print("Sorted: ",sorted_ids)
    #size = len(sorted_ids)
    for i in range(len(sorted_ids)-1):
        temp_ids.append(sorted_ids[i])

        if sorted_ids[i]+1 != sorted_ids[i+1] :
            temp_ids.insert(i+1,"V")
    print(temp_ids)
    #print(sorted_ids)


tickets_list = ['T20', 'T5', 'T10', 'T1', 'T2', 'T8', 'T16', 'T17', 'T9', 'T4', 'T12', 'T13', 'T18']
print("Ticket ids of all the available students :")
print(tickets_list)
result=arrange_tickets(tickets_list)

实际结果： [1,2，'V'，4，'V'，5,8，'V'，9，'V'，10,12，'V'，13,16,17,18]

预期结果： [T1，T2，V，T4，T5，V，V，T8，T9，T10，V，T12，T13，V，V，T16，T17，T18，V，T20]

Answer 1

这是一个解决方案：

sorted_ids=[1, 2, 4, 5, 8, 9, 10, 12, 13, 16, 17, 18, 20]

def arrange(inList):
    newList = []
    newList.append('T'+str(inList[0]))
    for i in range(1,len(inList)):
        diff = inList[i] - inList[i-1]
        if diff > 1:
            for d in range(diff-1):
                newList.append('V')
            newList.append('T'+str(inList[i]))
        else:
            newList.append('T'+str(inList[i]))
    return newList

print(arrange(sorted_ids))

输出：

['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 2

这是另一个值得考虑的解决方案：

sorted_ids=[1, 2, 4, 5, 8, 9, 10, 12, 13, 16, 17, 18, 20]

for i in range(min(sorted_ids), max(sorted_ids)): 
     if sorted_ids[i] != i + 1: 
         sorted_ids.insert(i, 'V')

final_list = [ "T" + str(x) if isinstance(x, int) else x for x in sorted_ids]

结果：

['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 3

这是一个列表理解，它可以让你得到你想要的：

sorted_ids=[1, 2, 4, 5, 8, 9, 10, 12, 13, 16, 17, 18, 20]
a = sorted_ids[0]
b = sorted_ids[-1]
nums = set(sorted_ids)
expected = ["T" + str(i) if i in nums else 'V' for i in range(a,b+1)]
print(expected)

输出：

['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 4

temp_ids.insert(i+1,"V") 

这是一个麻烦的陈述。 以下列方式更新您的代码

temp_ids=[]

for i in range(len(sorted_ids)-1):
    temp_ids.append(sorted_ids[i])

    if sorted_ids[i]+1 != sorted_ids[i+1] :
        for i in range(sorted_ids[i+1]-sorted_ids[i]-1):
            temp_ids.append("V") # appends as many V's as required

temp_ids.append(sorted_ids[-1]) # appends last element

这应该工作假设排序数组是[1,2,6]

所以我们期望的输出应该是[1,2，'V'，'V'，'V'，6]。 所以每一次

sorted_ids[i]+1 != sorted_ids[i+1]

条件成立，我们将不得不附加几个V的数量。 现在要确定我们追加多少个V，看看在2到6之间，将附加3个V. 所以通常我们追加（sorted_ids [i + 1] - sorted [i] -1）V's。

现在看到这一行

for i in range(len(sorted_ids)-1):

由于这一行，我们的列表仅在[1,2,6]中运行[1,2]，并且我们永远不会在For循环中追加6，所以在退出For循环之后它会被追加。

Answer 5

首先考虑列表中的id应该是什么，假设它们从1开始并以最大的id出现。 然后检查每个预期的id是否实际存在，如果没有，则在那里放置“V”。 作为副作用，这也排序列表。

def arrange_tickets(tickets_list):
    ids = [int(ticket[1:]) for ticket in tickets_list]
    expected_ids = range(1, max(ids) + 1)
    return ["T%d" % n if n in ids else "V" for n in expected_ids]

tickets_list = ['T20', 'T5', 'T10', 'T1', 'T2', 'T8', 'T16', 'T17', 'T9', 'T4', 'T12', 'T13', 'T18']
print("Ticket ids of all the available students :")
print(tickets_list)
result=arrange_tickets(tickets_list)
print(result)   

结果：

Ticket ids of all the available students :
['T20', 'T5', 'T10', 'T1', 'T2', 'T8', 'T16', 'T17', 'T9', 'T4', 'T12', 'T13', 'T18']

['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 6

您可以使用此itertools 配方首先对连续数字进行分组：

from itertools import groupby
from operator import itemgetter

def groupby_consecutive(lst):
    for _, g in groupby(enumerate(lst), lambda x: x[0] - x[1]):
        yield list(map(itemgetter(1), g))

sorted_ids = [1, 2, 4, 5, 8, 9, 10, 12, 13, 16, 17, 18, 20]
print(list(groupby_consecutive(lst=sorted_ids)))
# [[1, 2], [4, 5], [8, 9, 10], [12, 13], [16, 17, 18], [20]]

然后你可以创建一个函数，从前面的分组中获取散布的V值：

def interperse(lst):
    for x, y in zip(lst, lst[1:]):
        yield ["V"] * (y[0] - x[-1] - 1)

groups = list(groupby_consecutive(lst))
print(list(interperse(groups)))
# [['V'], ['V', 'V'], ['V'], ['V', 'V'], ['V']]

然后你最终可以将上述结果压缩在一起：

def add_prefix(lst, prefix):
    return [prefix + str(x) for x in lst]

def create_sequences(lst, prefix='T'):
    groups = list(groupby_consecutive(lst))
    between = list(interperse(groups))

    result = add_prefix(groups[0], prefix)
    for x, y in zip(between, groups[1:]):
        result.extend(x + add_prefix(y, prefix))

    return result

sorted_ids = [1, 2, 4, 5, 8, 9, 10, 12, 13, 16, 17, 18, 20]
print(create_sequences(lst=sorted_ids))
# ['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 7

在一次拍摄中，直接形成原始阵列

array = ['T20', 'T5', 'T10', 'T1', 'T2', 'T8', 'T16', 'T17', 'T9', 'T4', 'T12', 'T13', 'T18']

您可以定义执行所有工作的方法：

def add_vs_between_not_cons(array):
  iterable = sorted(array, key= lambda x: int(x[1:]))
  i, size = 0, len(iterable)
  while i < size:
    delta = int(iterable[i][1:]) - int(iterable[i-1][1:])
    for _ in range(delta-1):
      yield "V"
    yield iterable[i]
    i += 1

所以，你可以打电话：

print(list(add_vs_between_not_cons(array)))

#=> ['T1', 'T2', 'V', 'T4', 'T5', 'V', 'V', 'T8', 'T9', 'T10', 'V', 'T12', 'T13', 'V', 'V', 'T16', 'T17', 'T18', 'V', 'T20']

Answer 8

我的infytq查询解决方案：

def arrange_tickets(tickets_list):
    ids = [int(ticket[1:]) for ticket in tickets_list]
    expected_ids = range(1, max(ids) + 1)
    listt=["T%d" % n if n in ids else "V" for n in expected_ids]
    list1=listt[0:10]
    list2=listt[11:]
    for i in range(10):
        if 'V' in list2:
            list2.remove('V')
    for j in range(0,len(list2)):
        for n, i in enumerate(list1):
            if i == 'V':
                list1[n] = list2[j]
                j+=1
    return list1
tickets_list = ['T5','T7','T1','T2','T8','T15','T17','T19','T6','T12','T13']
print("Ticket ids of all the available students :")
print(tickets_list)
result=arrange_tickets(tickets_list)
print()
print("Ticket ids of the ten students in Group-1:")
print(result[0:10])