用python循环中的不同子字符串替换字符串的相同子字符串出现

Question

我是 python 的新手，我想使用 python 用不同的子字符串替换特定字符串的相同子字符串出现。 我已经尝试了 python 的 .replace() 函数，但它用新的子字符串替换了所有出现的地方。 问题示例如下。

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字符串=“我是一个学生和一个老师”在这里，我希望通过添加额外的字符的字符串替换子“为”与“XAS”和“青年大使计划”。 最终的结果应该是“我是个学生XAS以及亚斯老师”

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我尝试过的代码：

string = "I am a student as well as a teacher"
 occurrences = re.findall("as", string)
 substr = ["xas","yas"]
 i = 0
 for occur in occurrences:
     string = string.replace(occur, substr[i])
     i = i + 1`

Answer 1

您可以通过以下方式通知更换它应该更换多少次

s = "I am a student as well as a teacher"
s = s.replace("as","xxx",1)
print(s) #I am a student xxx well as a teacher
s = s.replace("as","yyy",1)
print(s) #I am a student xxx well yyy a teacher

编辑：第一替换as与xas和第二as与yas需要不同的方法

s = "I am a student as well as a teacher"
repl = ["xas","yas"]
s = s.split("as")
for i in repl:
    s = [i.join(s[:2])]+s[2:]
s = s[0]
print(s) #I am a student xas well yas a teacher

注意，该解决方案假定的元素的数目repl是exatcly等于数量的as在s 。

Answer 2

您也可以使用正则表达式：

substr = ["xxx","yyy"]

def replace_with(_):
    """Returns first value of substr and removes it."""
    return substr.pop(0)

import re

string = "I am a student as well as a teacher"

print(re.sub("as",replace_with,string)) 

输出：

I am a student xxx well yyy a teacher

但是Daweo 使用 str.replace () 且限制为 1 的解决方案更优雅。