[英]Queryset in one to many relation
我正在尝试获取具有相关元素的Json
元素
我有两张桌子, Service
和Room
。 一项服务有许多房间。 我想获得room_id = x
的服务。
楷模
class Service(models.Model):
name = models.CharField(max_length=255, blank=True, null=True)
class Meta:
managed = True
db_table = 'Service'
class Room(models.Model):
name = models.CharField(max_length=255, blank=True, null=True)
service = models.ForeignKey(Service, models.DO_NOTHING, blank=True,
null=True)
class Meta:
managed = True
db_table = 'Room'
序列化器
class ServiceSerializer(serializers.ModelSerializer):
room_set = RoomSerializer(many=True, read_only=True)
class Meta:
model = Service
fields = ('name','room_set')
class RoomSerializer(serializers.ModelSerializer):
class Meta:
model = Room
fields = '__all__'
看法
queryset = Service.objects.filter(room__id=1)
serializer = ServiceSerializer(queryset, many=True)
return JsonResponse(serializer.data, safe=False)
我期待这样的 Json:
{
"name": "Hotel1",
"room_set": [
{
"id": 1,
"name": "Room1"
},
但我明白了:
{
"name": "Hotel1",
"room_set": [
{
"id": 1,
"name": "Room1",
},
{
"id": 2,
"name": "Room2",
},
{
"id": 3,
"name": "Room3",
}
}
是否有可能获得像我期望的那样的 json?
您可以通过添加带有过滤查询集的自定义Prefetch
对象 [Django-doc]来修补该集合,例如:
from django.db.models import Prefetch
queryset = Service.objects.filter(
room__id=1
).prefetch_related(
Prefetch('room_set', queryset=Room.objects.filter(id=1), to_attr='room_set1')
)
serializer = ServiceSerializer(queryset, many=True)
return JsonResponse(serializer.data, safe=False)
并让Serializer
解析新的相关管理器:
class ServiceSerializer(serializers.ModelSerializer):
room_set = RoomSerializer(many=True, read_only=True, source='room_set1')
class Meta:
model = Service
fields = ('name','room_set1')
class RoomSerializer(serializers.ModelSerializer):
class Meta:
model = Room
fields = '__all__'
您可以通过序列化器上下文传递房间 id 并在SerializerMethodField() 中进行相应的过滤
class ServiceSerializer(serializers.ModelSerializer):
rooms = serializers.SerializerMethodField()
class Meta:
model = Service
fields = ('name','rooms')
get_rooms(self,service):
room_id = self.get_context('room')
if room_id:
queryset = service.rooms_set.filter(id=room_id)
return RoomSerializer(queryset,many=True).data
return RoomSerializer(service.rooms_set.all(),many=True).data
serializer = ServiceSerializer(queryset, many=True,context={'room':1})
return JsonResponse(serializer.data, safe=False)
这是如何通过序列化程序完成它并且它是高度可定制的, Willem Van Onsem的回答足够简短,但它也需要两个与我相同的查询。
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