[英]Creating new column that flags row based on conditions
我正在尝试过滤称为df
数据df
structure(list(ï..ID = structure(c(2L, 1L, 4L, 6L, 3L, 7L, 5L,
8L), .Label = c("Jay ", "Jim", "Jim ", "John ", "Mike ", "Peter",
"Peter ", "Tom"), class = "factor"), Target1 = structure(c(8L,
4L, 6L, 5L, 2L, 1L, 3L, 7L), .Label = c("Andreas", "Cheyne",
"Frank", "John", "Mickey", "Raj", "Sarah", "Timothy"), class = "factor"),
Target2 = structure(c(4L, 3L, 1L, 5L, 2L, 1L, 1L, 1L), .Label = c("",
"Jake", "Peter", "Timothy ", "Tommy "), class = "factor"),
Parter1 = structure(c(3L, 2L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("",
"Mike ", "Timothy"), class = "factor"), Parter2 = structure(c(1L,
2L, 1L, 1L, 1L, 1L, 1L, 1L), .Label = c("", "Peter"), class = "factor")), class = "data.frame", row.names = c(NA,
-8L))
我试图过滤数据框,以便如果出现在此向量x
的名称
x=c("Raj", "Timothy")
在第2-5列中显示2次以上,该行将具有一个全新的变量,称为flag
,如果名称显示2次以上,则flag = 1;如果名称显示2次以上,则flag = 0。
在Base R中,我们可以使用apply
, MARGIN = 1
(逐行)
df$flag <- as.integer(apply(df, 1, function(row) sum(row %in% x)) > 2)
df
# ï..ID Target1 Target2 Parter1 Parter2 flag
#1 Jim Timothy Timothy Timothy 1
#2 Jay John Peter Mike Peter 0
#3 John Raj 0
#4 Peter Mickey Tommy 0
#5 Jim Cheyne Jake 0
#6 Peter Andreas 0
#7 Mike Frank 0
#8 Tom Sarah 0
apply
将数据帧转换为矩阵,可能会变慢一些时间。 您可以避免使用具有相同逻辑的sapply
进行apply
调用
df$flag <- as.integer(sapply(1:nrow(df), function(i) sum(df[i, ] %in% x)) > 2)
另一种写法
df$flag <- as.integer(colSums(sapply(1:nrow(df), function(i) df[i, ] %in% x)) > 2)
PS-名称中有一些空格,我必须先运行
df[] <- lapply(df, trimws)
删除它们。
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