通过比较四个列表中的值来分配分数

Question

我有四个清单。 我需要将perfect_list中的每个值与x，y和z中的每个项目进行比较，并相应地为其分配一个分数。 如果perfect_list中的值在x中，则分配一个值x。 如果在x和y中找到它，则将其赋值为5。这里的问题是它正在考虑所有条件。 如果在x和y中找到它，那么它应该只打印5，但是打印3和5。

perfect_list=[0, 1, 2, 3, 4, 5, 6, 7, 8, 10, 14, 16, 17, 18, 19, 20, 21, 22]
x=[0, 1, 2, 3, 4, 18, 19, 20, 21, 22, 100, 100, 100, 100, 100, 100, 100, 100]
y=[2, 3, 4, 8, 14, 17, 20, 21, 100, 100, 100, 100, 100, 100,  100, 100, 100, 100]
z=[5, 1, 6, 3, 7, 10, 16, 21, 22, 2, 8, 100, 100, 100, 100, 100, 100, 100]
score_list=[]
for n in perfect_list:
     if n in x:
        print "Present in x"
        score=3
        score_list.append(score)
        print score

     if n in y:
        print "Present in y"
        score=2
        score_list.append(score)
        print score
     if n in z:
        print "Present in z"
        score=1
        score_list.append(score)
        print score

     #elif n in x or n in y or n in z:
             #print "Not present in all"

     if n in x and n in y and n not in z:
        print "Present in x and y"
        score=5
        score_list.append(score)
        print score
     if n in x and n in z and n not in y:
        print "Present in x and z"
        score=4
        score_list.append(score)
        print score
     if n in y and n in z and n not in x:
        print "Present in z and y" 
        score=3
        score_list.append(score)
        print score
     if n not in x and n  in y and n  in z:
        print "Present in all"
        score=6
        score_list.append(score)
        print score
score_list.append(score)


Output:
Scores are:
[3, 3, 1, 4, 3, 2, 1, 3, 2, 1, 3, 2, 5, 1, 1, 1, 2, 1, 3, 6, 1, 2, 1, 2, 3, 3, 3, 2, 5, 3, 2, 1, 3, 1, 4, 4]

Answer 1

for n in perfect_list:
     if n in x and n in y and n in z:
             print "Present in all"
     if n in x or n in y or n in z:
             print "Not present in all"
     if n not in x and n not in y and n not in z:
             print "Not present in any"

您可以使用此语法进行检查，然后根据需要分配分数。 喜欢：

if n in x:
    score=3

Answer 2

这个答案假设以下

score if found in x = 3

score if found in y = 2

score if found in x = 1

score if found in x and y = score with x + score with y

score if found in y and z = score with y + score with z

score if found in x and z = score with x + score with z

score if found in x and y and z = score with x + score with y + score z

注意：此处使用的map函数可在数组上进行映射，同时对数组中的每个项目执行功能，文档可在此处找到https://www.programiz.com/python-programming/methods/built-in/map

#Declare Constants For Score
X_SCORE = 3
Y_SCORE = 2
Z_SCORE = 1

compare_list=[0, 1, 2, 3, 4, 5, 6, 7, 8, 10, 14, 16, 17, 18, 19, 20, 21, 22]
x=[0, 1, 2, 3, 4, 18, 19, 20, 21, 22, 100, 100, 100, 100, 100, 100, 100, 100]
y=[2, 3, 4, 8, 14, 17, 20, 21, 100, 100, 100, 100, 100, 100,  100, 100, 100, 100]
z=[5, 1, 6, 3, 7, 10, 16, 21, 22, 2, 8, 100, 100, 100, 100, 100, 100, 100]

#Function calculateScore accepts an item from the array for each iteration of the array
def calculateScore(item):
    score = 0
    if item in x:
        score = X_SCORE
    if item in y:
        score = Y_SCORE
    if item in z:
        score = Z_SCORE
    if item in x and item in y:
        score = X_SCORE + Y_SCORE
    if item in x and item in z:
        score = X_SCORE + Z_SCORE
    if item in y and item in z:
        score = Y_SCORE + Z_SCORE
    if item in y and item in x and item in z:
        score = X_SCORE + Y_SCORE + Z_SCORE
    return score

# map(functionToPerformAction, ArrayToPerformActionOn)
# This will return an array
final_score = map(calculateScore, compare_list)

print(list(final_score))

# Output
# [3, 4, 6, 6, 5, 1, 1, 1, 3, 1, 2, 1, 2, 3, 3, 5, 6, 4]